It is given that for a common type of reaction the value of K < < 1 . The assumption made when solving the equilibrium concentrations for reactions with small K values and the procedure followed if the ‘ 5 % rule’ fails are to be stated. Concept introduction: If the error in the equilibrium concentration calculated is less than 5 % , the assumption made is stated to be correct. This is known as the ‘ 5 % rule’. If the error exceeds the 5 % value, then the quadratic formula is used for calculating the equilibrium concentrations. To determine: The assumption made when solving the equilibrium concentrations for reactions with small K values and the procedure followed if the ‘ 5 % rule’ fails.
It is given that for a common type of reaction the value of K < < 1 . The assumption made when solving the equilibrium concentrations for reactions with small K values and the procedure followed if the ‘ 5 % rule’ fails are to be stated. Concept introduction: If the error in the equilibrium concentration calculated is less than 5 % , the assumption made is stated to be correct. This is known as the ‘ 5 % rule’. If the error exceeds the 5 % value, then the quadratic formula is used for calculating the equilibrium concentrations. To determine: The assumption made when solving the equilibrium concentrations for reactions with small K values and the procedure followed if the ‘ 5 % rule’ fails.
Solution Summary: The author explains how the quadratic equation method is used for solving the equilibrium concentrations for reactions with small K values and the procedure followed if the 5% rule fails.
Interpretation: It is given that for a common type of reaction the value of
K<<1. The assumption made when solving the equilibrium concentrations for reactions with small
K values and the procedure followed if the ‘
5% rule’ fails are to be stated.
Concept introduction: If the error in the equilibrium concentration calculated is less than
5%, the assumption made is stated to be correct. This is known as the ‘
5% rule’. If the error exceeds the
5% value, then the quadratic formula is used for calculating the equilibrium concentrations.
To determine: The assumption made when solving the equilibrium concentrations for reactions with small
K values and the procedure followed if the ‘
5% rule’ fails.
(c) The following data have been obtained for the hydrolysis of sucrose, C12H22O11, to
glucose, C6H12O6, and fructose C6H12O6, in acidic solution:
C12H22O11 + H2O → C6H12O6 + C6H12O6
[sucrose]/mol dm³
t/min
0
0.316
14
0.300
39
0.274
60
0.256
80
0.238
110
0.211
(i) Graphically prove the order of the reaction and determine the rate constant of the
reaction.
(ii) Determine the half-life, t½ for the hydrolysis of sucrose.
(III) adsorbent
(b) Adsorption of the hexacyanoferrate (III) ion, [Fe(CN)6] ³, on y-Al2O3 from aqueous
solution was examined. The adsorption was modelled using a modified Langmuir
isotherm, yielding the following values of Kat pH = 6.5:
(ii)
T/K
10-10 K
280
2.505
295
1.819
310
1.364
325
1.050
Determine the enthalpy of adsorption, AadsHⓇ.
If the reported value of entropy of adsorption, Aads Se = 146 J K-1 mol-1 under the above
conditions, determine Aads Gº.
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