Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Textbook Question
Chapter 12, Problem 39SDP
Using the method of inscribed circles, shown in Fig. 12.2, justify the trend shown in Fig. 12.3.
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A piece with a height of 120 mm and a diameter of 75 mm can be increased to 80 mm in height by pile-forging.is reduced. The coefficient of friction between the workpiece and the mold is 0.13. Flow curve of the workpiece, 165It is defined by a strength coefficient of MPa and a hardening exponent of 0.24. force during operationCalculate at the moments given below and obtain the force-workpiece height graph(1) as soon as it reaches the yield point (yield strain = 0.002),(2) height h = 115 mm,(3) height h = 110 mm,(4) height h = 105mm,(5) height h = 100mm,(6) height h=95mm,(7) height h = 90 mm,(8) height h = 85mm,(9) height h = 80 mm,
Question 2. It is reduced to 80 mm with forging by stacking a part with a height of 120 mm and a
diameter of 75 mm. The friction coefficient between the workpiece and the mold is 0.13. The flow
curve of the workpiece is defined by a strength coefficient of 165 MPa and a ping-top of
0.24. Calculate the force during the process at the moments given below and obtain the
force-workpiece height graph
(1) as soon as it reaches the flow point (flow unit shape change = 0.002),
(2) height h = 115 mm,
(3) height h = 110 mm,
(4) height h = 105 mm,
(5) height h = 100 mm,
(6) height h = 95 mm,
(7) height h = 90 mm,
(8) height h = 85 mm,
(9) height h = 80 mm,
Chapter 12 Solutions
Manufacturing Engineering & Technology
Ch. 12 - Why are steels more difficult to cast than cast...Ch. 12 - What is the significance of hot spots in metal...Ch. 12 - What is shrinkage allowance? Machining allowance?Ch. 12 - Explain the reason for drafts in molds.Ch. 12 - Prob. 5RQCh. 12 - What are light castings and where are they used...Ch. 12 - Name the types of cast irons generally available,...Ch. 12 - Comment on your observations regarding Fig. 12.5.Ch. 12 - Describe the difference between a runner and a...Ch. 12 - What is the difference between machining allowance...
Ch. 12 - What is dross? Can it be eliminated?Ch. 12 - Describe your observation concerning the design...Ch. 12 - If you need only a few castings of the same...Ch. 12 - Do you generally agree with the cost ratings in...Ch. 12 - Describe the nature of the design differences...Ch. 12 - Note in Fig. 12.5 that the ductility of some cast...Ch. 12 - Do you think that there will be fewer defects in a...Ch. 12 - Explain the difference in the importance of drafts...Ch. 12 - What type of cast iron would be suitable for...Ch. 12 - Explain the advantages and limitations of sharp...Ch. 12 - Explain why the elastic modulus, E, of gray cast...Ch. 12 - If you were to incorporate lettering or numbers on...Ch. 12 - The general design recommendations for a well in...Ch. 12 - The heavy regions of parts typically are placed in...Ch. 12 - What are the benefits and drawbacks to having a...Ch. 12 - When designing patterns for casting, patternmakers...Ch. 12 - Using the information given in Table 12.2, develop...Ch. 12 - The part in Figure P12.28 is to be cast of 10% Sn...Ch. 12 - Describe the general design considerations...Ch. 12 - Add more examples of applications to those shown...Ch. 12 - Explain how ribs and serrations are helpful in...Ch. 12 - List casting processes that are suitable for...Ch. 12 - Small amounts of slag and dross often persist...Ch. 12 - If you need only a few units of a particular...Ch. 12 - For the cast metal wheel illustrated in Fig....Ch. 12 - Assume that the introduction to this chapter is...Ch. 12 - In Fig. P12.37, the original casting design shown...Ch. 12 - An incorrect and a correct design for casting are...Ch. 12 - Using the method of inscribed circles, shown in...Ch. 12 - A growing trend is the production of patterns and...Ch. 12 - Repeat Problem 12.40 for the case where (a) a...
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