Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 12, Problem 14QLP
Do you generally agree with the cost ratings in Table 12.6? If so, why?
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Chapter 12 Solutions
Manufacturing Engineering & Technology
Ch. 12 - Why are steels more difficult to cast than cast...Ch. 12 - What is the significance of hot spots in metal...Ch. 12 - What is shrinkage allowance? Machining allowance?Ch. 12 - Explain the reason for drafts in molds.Ch. 12 - Prob. 5RQCh. 12 - What are light castings and where are they used...Ch. 12 - Name the types of cast irons generally available,...Ch. 12 - Comment on your observations regarding Fig. 12.5.Ch. 12 - Describe the difference between a runner and a...Ch. 12 - What is the difference between machining allowance...
Ch. 12 - What is dross? Can it be eliminated?Ch. 12 - Describe your observation concerning the design...Ch. 12 - If you need only a few castings of the same...Ch. 12 - Do you generally agree with the cost ratings in...Ch. 12 - Describe the nature of the design differences...Ch. 12 - Note in Fig. 12.5 that the ductility of some cast...Ch. 12 - Do you think that there will be fewer defects in a...Ch. 12 - Explain the difference in the importance of drafts...Ch. 12 - What type of cast iron would be suitable for...Ch. 12 - Explain the advantages and limitations of sharp...Ch. 12 - Explain why the elastic modulus, E, of gray cast...Ch. 12 - If you were to incorporate lettering or numbers on...Ch. 12 - The general design recommendations for a well in...Ch. 12 - The heavy regions of parts typically are placed in...Ch. 12 - What are the benefits and drawbacks to having a...Ch. 12 - When designing patterns for casting, patternmakers...Ch. 12 - Using the information given in Table 12.2, develop...Ch. 12 - The part in Figure P12.28 is to be cast of 10% Sn...Ch. 12 - Describe the general design considerations...Ch. 12 - Add more examples of applications to those shown...Ch. 12 - Explain how ribs and serrations are helpful in...Ch. 12 - List casting processes that are suitable for...Ch. 12 - Small amounts of slag and dross often persist...Ch. 12 - If you need only a few units of a particular...Ch. 12 - For the cast metal wheel illustrated in Fig....Ch. 12 - Assume that the introduction to this chapter is...Ch. 12 - In Fig. P12.37, the original casting design shown...Ch. 12 - An incorrect and a correct design for casting are...Ch. 12 - Using the method of inscribed circles, shown in...Ch. 12 - A growing trend is the production of patterns and...Ch. 12 - Repeat Problem 12.40 for the case where (a) a...
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- (Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forwardProblem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forward
- Problem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forwardAn experimental setup is being built to study the flow in a large water main (i.e., a large pipe). The water main is expected to convey a discharge (Qp). The experimental tube will be built at a length scale of 1/20 of the actual water main. After building the experimental setup, the pressure drop per unit length in the model tube (APm/Lm) is measured. Problem (20): Given the value of APm/Lm [kPa/m], and assuming pressure coefficient similitude, calculate the drop in the pressure per unit length of the water main (APP/Lp) in [Pa/m]. Givens: AP M/L m = 590.637 kPa/m meen Answers: ( 1 ) 59.369 Pa/m ( 2 ) 73.83 Pa/m (3) 95.443 Pa/m ( 4 ) 44.444 Pa/m *******arrow_forward
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- Problem 19: Determine the force in members HG, HE, and DE of the truss, and state if the members are in tension or compression. 4 ft K J I H G B C D E F -3 ft -3 ft 3 ft 3 ft 3 ft- 1500 lb 1500 lb 1500 lb 1500 lb 1500 lbarrow_forwardProblem 14: Determine the reactions at the pin A, and the tension in cord. Neglect the thickness of the beam. F1=26kN F2 13 12 80° -2m 3marrow_forwardProblem 22: Determine the force in members GF, FC, and CD of the bridge truss and state if the members are in tension or compression. F 15 ft B D -40 ft 40 ft -40 ft 40 ft- 5 k 10 k 15 k 30 ft Earrow_forward
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