Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Textbook Question
Chapter 12, Problem 17QLP
Do you think that there will be fewer defects in a casting made by gravity pouring versus one made by pouring under pressure? Explain.
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For sand-casting a steel rectangular plate with dimensions 80mm×120mm×20mm, a cylindrical
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Chapter 12 Solutions
Manufacturing Engineering & Technology
Ch. 12 - Why are steels more difficult to cast than cast...Ch. 12 - What is the significance of hot spots in metal...Ch. 12 - What is shrinkage allowance? Machining allowance?Ch. 12 - Explain the reason for drafts in molds.Ch. 12 - Prob. 5RQCh. 12 - What are light castings and where are they used...Ch. 12 - Name the types of cast irons generally available,...Ch. 12 - Comment on your observations regarding Fig. 12.5.Ch. 12 - Describe the difference between a runner and a...Ch. 12 - What is the difference between machining allowance...
Ch. 12 - What is dross? Can it be eliminated?Ch. 12 - Describe your observation concerning the design...Ch. 12 - If you need only a few castings of the same...Ch. 12 - Do you generally agree with the cost ratings in...Ch. 12 - Describe the nature of the design differences...Ch. 12 - Note in Fig. 12.5 that the ductility of some cast...Ch. 12 - Do you think that there will be fewer defects in a...Ch. 12 - Explain the difference in the importance of drafts...Ch. 12 - What type of cast iron would be suitable for...Ch. 12 - Explain the advantages and limitations of sharp...Ch. 12 - Explain why the elastic modulus, E, of gray cast...Ch. 12 - If you were to incorporate lettering or numbers on...Ch. 12 - The general design recommendations for a well in...Ch. 12 - The heavy regions of parts typically are placed in...Ch. 12 - What are the benefits and drawbacks to having a...Ch. 12 - When designing patterns for casting, patternmakers...Ch. 12 - Using the information given in Table 12.2, develop...Ch. 12 - The part in Figure P12.28 is to be cast of 10% Sn...Ch. 12 - Describe the general design considerations...Ch. 12 - Add more examples of applications to those shown...Ch. 12 - Explain how ribs and serrations are helpful in...Ch. 12 - List casting processes that are suitable for...Ch. 12 - Small amounts of slag and dross often persist...Ch. 12 - If you need only a few units of a particular...Ch. 12 - For the cast metal wheel illustrated in Fig....Ch. 12 - Assume that the introduction to this chapter is...Ch. 12 - In Fig. P12.37, the original casting design shown...Ch. 12 - An incorrect and a correct design for casting are...Ch. 12 - Using the method of inscribed circles, shown in...Ch. 12 - A growing trend is the production of patterns and...Ch. 12 - Repeat Problem 12.40 for the case where (a) a...
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- 2. In the casting of steel under certain mould conditions, the mould constant in Chvorinov's rule is known to be 4.0 min/cm?, based on previous experience. The casting is a flat plate whose length is 25 cm, width is 8 cm, and thickness is 2.5 cm. Exponent n is taken to have a value of 2. Determine how long it will take for the casting to solidify.arrow_forwarda riser in the shape of a sphere is to be designed for a sand casting mold. the casting is a rectangular plate, with length 200mm, width 100mm, and thickness 18mm. if the total solidification time of the casting itself is known to be 3.5 mm, determine the diameter of the riser so that it will take 25% longer for the riser to solidify. assume a value of 2 for ‘n’ m( the exponent in chvorinov’s rule). know the volume and surface area of a sphere.arrow_forwardYou were required to make 1000 simple small parts in aluminum. Would using a permanent mold be less expensive per part then preparing 1000 sand molds explain?arrow_forward
- A riser in the shape of a sphere is to be designed for a sand casting mould at Simon Castings. The casting is a rectangular plate, with length = 400 mm, width = 250 mm, and thickness = 15 mm. If the total solidification time of the casting itself is known to be 7 min, determine the diameter of the riser so that it will take 30% longer for the riser to solidify.arrow_forwardDoarrow_forwardI am in a hurry, I need the answer as soon as possible, please help.arrow_forward
- When designing patterns for casting, patternmakers use special rulers that automatically incorporate solid shrinkage allowances into their designs. For example, a 12-in. patternmaker’s ruler is longer than 1 foot. How long should a patternmaker’s ruler be for making patterns for (a) aluminum castings and (b) high-manganese steel?arrow_forwardParvinbhaiarrow_forwardManufacturing Processesarrow_forward
- compute the diameter of the sphere (mm) that will freeze in the same time in same casting process with a 62.5mm x 150mm x 225mm plate. Assume that constant mold for this casting is 55 mm^2/sarrow_forwardA flat plate is to be cast in an open mold whose bottom has a square shape that is 200 mm by 200 mm. The mold is 40 mm deep. A total of 106 mm3 of molten aluminum is poured into the mold. Solidification shrinkage is known to be 6.0%. The linear shrinkage due to thermal contraction after solidification is 1.3%. If the availability of molten metal in the mold allows the square shape of the cast plate to maintain its 200 mm by 200 mm dimensions until solidification is completed, determine the final dimensions of the plate.arrow_forwardEx.1// A disk 40 cm in diameter and 5 cm thick is to be cast of pure aluminum in an open mold casting operation. The melting temperature of aluminum = 660°C, and the pouring temperature will be 800°C. Assume that the amount of aluminum heated will be 5% more than what is needed to fill the mold cavity. Compute the amount of heat that must be added to the metal to heat it to the pouring temperature, starting from a room temperature of 25°C. The heat of fusion of aluminum = 389.3 J/g... Assume the specific heat has the same value for solid and molten aluminumarrow_forward
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