
Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Textbook Question
Chapter 12, Problem 3RQ
What is shrinkage allowance? Machining allowance?
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Liquid hexane flows through a counter flow heat exchanger at 5 m3/h as shown in Figure E5.5.The hexane enters the heat exchanger at 90°C. Water, flowing at 5 m3/h, is used to cool the hexane.The water enters the heat exchanger at 15°C. The UA product of the heat exchanger is found to be2.7 kW/K. Determine the outlet temperatures of the hot and cold fluids and the heat transfer ratebetween them using LMTD method.
Determine the fluid outlet temperatures and the heat transfer rate for the counter flow heatexchanger described in Problem 3 using the ε-NTU model. Assume that the properties can beevaluated at the given fluid inlet temperatures.
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Chapter 12 Solutions
Manufacturing Engineering & Technology
Ch. 12 - Why are steels more difficult to cast than cast...Ch. 12 - What is the significance of hot spots in metal...Ch. 12 - What is shrinkage allowance? Machining allowance?Ch. 12 - Explain the reason for drafts in molds.Ch. 12 - Prob. 5RQCh. 12 - What are light castings and where are they used...Ch. 12 - Name the types of cast irons generally available,...Ch. 12 - Comment on your observations regarding Fig. 12.5.Ch. 12 - Describe the difference between a runner and a...Ch. 12 - What is the difference between machining allowance...
Ch. 12 - What is dross? Can it be eliminated?Ch. 12 - Describe your observation concerning the design...Ch. 12 - If you need only a few castings of the same...Ch. 12 - Do you generally agree with the cost ratings in...Ch. 12 - Describe the nature of the design differences...Ch. 12 - Note in Fig. 12.5 that the ductility of some cast...Ch. 12 - Do you think that there will be fewer defects in a...Ch. 12 - Explain the difference in the importance of drafts...Ch. 12 - What type of cast iron would be suitable for...Ch. 12 - Explain the advantages and limitations of sharp...Ch. 12 - Explain why the elastic modulus, E, of gray cast...Ch. 12 - If you were to incorporate lettering or numbers on...Ch. 12 - The general design recommendations for a well in...Ch. 12 - The heavy regions of parts typically are placed in...Ch. 12 - What are the benefits and drawbacks to having a...Ch. 12 - When designing patterns for casting, patternmakers...Ch. 12 - Using the information given in Table 12.2, develop...Ch. 12 - The part in Figure P12.28 is to be cast of 10% Sn...Ch. 12 - Describe the general design considerations...Ch. 12 - Add more examples of applications to those shown...Ch. 12 - Explain how ribs and serrations are helpful in...Ch. 12 - List casting processes that are suitable for...Ch. 12 - Small amounts of slag and dross often persist...Ch. 12 - If you need only a few units of a particular...Ch. 12 - For the cast metal wheel illustrated in Fig....Ch. 12 - Assume that the introduction to this chapter is...Ch. 12 - In Fig. P12.37, the original casting design shown...Ch. 12 - An incorrect and a correct design for casting are...Ch. 12 - Using the method of inscribed circles, shown in...Ch. 12 - A growing trend is the production of patterns and...Ch. 12 - Repeat Problem 12.40 for the case where (a) a...
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- I need help with a MATLAB code. This code just keeps running and does not give me any plots. I even reduced the tolerance from 1e-9 to 1e-6. Can you help me fix this? Please make sure your solution runs. % Initial Conditions rev = 0:0.001:2; g1 = deg2rad(1); g2 = deg2rad(3); g3 = deg2rad(6); g4 = deg2rad(30); g0 = deg2rad(0); Z0 = 0; w0 = [0; Z0*cos(g0); -Z0*sin(g0)]; Z1 = 5; w1 = [0; Z1*cos(g1); -Z1*sin(g1)]; Z2 = 11; w2 = [0; Z2*cos(g2); -Z2*sin(g2)]; [v3, psi3, eta3] = Nut_angle(Z2, g2, w2); plot(v3, psi3) function dwedt = K_DDE(~, w_en) % Extracting the initial condtions to a variable % Extracting the initial condtions to a variable w = w_en(1:3); e = w_en(4:7); Z = w_en(8); I = 0.060214; J = 0.015707; x = (J/I) - 1; y = Z - 1; s = Z; % Kinematic Differential Equations dedt = zeros(4,1); dedt(1) = pi*(e(3)*(s-w(2)-1) + e(2)*w(3) + e(4)*w(1)); dedt(2) = pi*(e(4)*(w(2)-1-s) + e(3)*w(1) - e(1)*w(3)); dedt(3) = pi*(-e(1)*(s-w(2)-1) - e(2)*w(1) + e(4)*w(3));…arrow_forwardalpha 1 is not zero alpha 1 can equal alpha 2 use velocity triangle to solve for alpha 1 USE MATLAB ONLY provide typed code solve for velocity triangle and dont provide copied answer Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, (leaving a stator in axial flow) R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',...…arrow_forward3. Find a basis of eigenvectors and diagonalize. 4 0 -19 7 a. b. 1-42 16 12-20 [21-61arrow_forward
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