Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
1st Edition
ISBN: 9780078682278
Author: McGraw-Hill, Berchie Holliday
Publisher: Glencoe/McGraw-Hill
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 1.2, Problem 2GCE
To determine
To find:
Expert Solution & Answer
Answer to Problem 2GCE
Explanation of Solution
Given information:
From the table,
Calculation:
Let’s substitute the value of
Thus, the value of
Chapter 1 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Ch. 1.1 - Prob. 1CFUCh. 1.1 - Prob. 2CFUCh. 1.1 - Prob. 3CFUCh. 1.1 - Prob. 4CFUCh. 1.1 - Prob. 5CFUCh. 1.1 - Prob. 6CFUCh. 1.1 - Prob. 7CFUCh. 1.1 - Prob. 8CFUCh. 1.1 - Prob. 9CFUCh. 1.1 - Prob. 10CFU
Ch. 1.1 - Prob. 11CFUCh. 1.1 - Prob. 12CFUCh. 1.1 - Prob. 13CFUCh. 1.1 - Prob. 14CFUCh. 1.1 - Prob. 15CFUCh. 1.1 - Prob. 16CFUCh. 1.1 - Prob. 17ECh. 1.1 - Prob. 18ECh. 1.1 - Prob. 19ECh. 1.1 - Prob. 20ECh. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.1 - Prob. 37ECh. 1.1 - Prob. 38ECh. 1.1 - Prob. 39ECh. 1.1 - Prob. 40ECh. 1.1 - Prob. 41ECh. 1.1 - Prob. 42ECh. 1.1 - Prob. 43ECh. 1.1 - Prob. 44ECh. 1.1 - Prob. 45ECh. 1.1 - Prob. 46ECh. 1.1 - Prob. 47ECh. 1.1 - Prob. 48ECh. 1.1 - Prob. 49ECh. 1.1 - Prob. 50ECh. 1.1 - Prob. 51ECh. 1.1 - Prob. 52ECh. 1.1 - Prob. 53ECh. 1.1 - Prob. 54ECh. 1.1 - Prob. 55ECh. 1.1 - Prob. 56ECh. 1.1 - Prob. 57ECh. 1.2 - Prob. 1GCECh. 1.2 - Prob. 2GCECh. 1.2 - Prob. 3GCECh. 1.2 - Prob. 4GCECh. 1.2 - Prob. 5GCECh. 1.2 - Prob. 1CFUCh. 1.2 - Prob. 2CFUCh. 1.2 - Prob. 3CFUCh. 1.2 - Prob. 4CFUCh. 1.2 - Prob. 5CFUCh. 1.2 - Prob. 6CFUCh. 1.2 - Prob. 7CFUCh. 1.2 - Prob. 8CFUCh. 1.2 - Prob. 9CFUCh. 1.2 - Prob. 10CFUCh. 1.2 - Prob. 11ECh. 1.2 - Prob. 12ECh. 1.2 - Prob. 13ECh. 1.2 - Prob. 14ECh. 1.2 - Prob. 15ECh. 1.2 - Prob. 16ECh. 1.2 - Prob. 17ECh. 1.2 - Prob. 18ECh. 1.2 - Prob. 19ECh. 1.2 - Prob. 20ECh. 1.2 - Prob. 21ECh. 1.2 - Prob. 22ECh. 1.2 - Prob. 23ECh. 1.2 - Prob. 24ECh. 1.2 - Prob. 25ECh. 1.2 - Prob. 26ECh. 1.2 - Prob. 27ECh. 1.2 - Prob. 28ECh. 1.2 - Prob. 29ECh. 1.2 - Prob. 30ECh. 1.2 - Prob. 31ECh. 1.2 - Prob. 32ECh. 1.2 - Prob. 33ECh. 1.2 - Prob. 34ECh. 1.2 - Prob. 35ECh. 1.2 - Prob. 36ECh. 1.2 - Prob. 37ECh. 1.2 - Prob. 38ECh. 1.2 - Prob. 39ECh. 1.3 - Prob. 1CFUCh. 1.3 - Prob. 2CFUCh. 1.3 - Prob. 3CFUCh. 1.3 - Prob. 4CFUCh. 1.3 - Prob. 5CFUCh. 1.3 - Prob. 6CFUCh. 1.3 - Prob. 7CFUCh. 1.3 - Prob. 8CFUCh. 1.3 - Prob. 9CFUCh. 1.3 - Prob. 10CFUCh. 1.3 - Prob. 11CFUCh. 1.3 - Prob. 12ECh. 1.3 - Prob. 13ECh. 1.3 - Prob. 14ECh. 1.3 - Prob. 15ECh. 1.3 - Prob. 16ECh. 1.3 - Prob. 17ECh. 1.3 - Prob. 18ECh. 1.3 - Prob. 19ECh. 1.3 - Prob. 20ECh. 1.3 - Prob. 21ECh. 1.3 - Prob. 22ECh. 1.3 - Prob. 23ECh. 1.3 - Prob. 24ECh. 1.3 - Prob. 25ECh. 1.3 - Prob. 26ECh. 1.3 - Prob. 27ECh. 1.3 - Prob. 28ECh. 1.3 - Prob. 29ECh. 1.3 - Prob. 30ECh. 1.3 - Prob. 31ECh. 1.3 - Prob. 32ECh. 1.3 - Prob. 33ECh. 1.3 - Prob. 34ECh. 1.3 - Prob. 35ECh. 1.3 - Prob. 36ECh. 1.3 - Prob. 37ECh. 1.3 - Prob. 38ECh. 1.3 - Prob. 39ECh. 1.3 - Prob. 40ECh. 1.3 - Prob. 41ECh. 1.3 - Prob. 42ECh. 1.3 - Prob. 43ECh. 1.3 - Prob. 44ECh. 1.3 - Prob. 45ECh. 1.3 - Prob. 46ECh. 1.3B - Prob. 1GCECh. 1.3B - Prob. 2GCECh. 1.3B - Prob. 3GCECh. 1.4 - Prob. 1CFUCh. 1.4 - Prob. 2CFUCh. 1.4 - Prob. 3CFUCh. 1.4 - Prob. 4CFUCh. 1.4 - Prob. 5CFUCh. 1.4 - Prob. 6CFUCh. 1.4 - Prob. 7CFUCh. 1.4 - Prob. 8CFUCh. 1.4 - Prob. 9CFUCh. 1.4 - Prob. 10CFUCh. 1.4 - Prob. 11ECh. 1.4 - Prob. 12ECh. 1.4 - Prob. 13ECh. 1.4 - Prob. 14ECh. 1.4 - Prob. 15ECh. 1.4 - Prob. 16ECh. 1.4 - Prob. 17ECh. 1.4 - Prob. 18ECh. 1.4 - Prob. 19ECh. 1.4 - Prob. 20ECh. 1.4 - Prob. 21ECh. 1.4 - Prob. 22ECh. 1.4 - Prob. 23ECh. 1.4 - Prob. 24ECh. 1.4 - Prob. 25ECh. 1.4 - Prob. 26ECh. 1.4 - Prob. 27ECh. 1.4 - Prob. 28ECh. 1.4 - Prob. 29ECh. 1.4 - Prob. 30ECh. 1.4 - Prob. 31ECh. 1.4 - Prob. 32ECh. 1.4 - Prob. 33ECh. 1.4 - Prob. 34ECh. 1.4 - Prob. 35ECh. 1.4 - Prob. 1MCQCh. 1.4 - Prob. 2MCQCh. 1.4 - Prob. 3MCQCh. 1.4 - Prob. 4MCQCh. 1.4 - Prob. 5MCQCh. 1.4 - Prob. 6MCQCh. 1.4 - Prob. 7MCQCh. 1.4 - Prob. 8MCQCh. 1.4 - Prob. 9MCQCh. 1.4 - Prob. 10MCQCh. 1.5 - Prob. 1CFUCh. 1.5 - Prob. 2CFUCh. 1.5 - Prob. 3CFUCh. 1.5 - Prob. 4CFUCh. 1.5 - Prob. 5CFUCh. 1.5 - Prob. 6CFUCh. 1.5 - Prob. 7CFUCh. 1.5 - Prob. 8CFUCh. 1.5 - Prob. 9CFUCh. 1.5 - Prob. 10CFUCh. 1.5 - Prob. 11CFUCh. 1.5 - Prob. 12ECh. 1.5 - Prob. 13ECh. 1.5 - Prob. 14ECh. 1.5 - Prob. 15ECh. 1.5 - Prob. 16ECh. 1.5 - Prob. 17ECh. 1.5 - Prob. 18ECh. 1.5 - Prob. 19ECh. 1.5 - Prob. 20ECh. 1.5 - Prob. 21ECh. 1.5 - Prob. 22ECh. 1.5 - Prob. 23ECh. 1.5 - Prob. 24ECh. 1.5 - Prob. 25ECh. 1.5 - Prob. 26ECh. 1.5 - Prob. 27ECh. 1.5 - Prob. 28ECh. 1.5 - Prob. 29ECh. 1.5 - Prob. 30ECh. 1.5 - Prob. 31ECh. 1.5 - Prob. 32ECh. 1.5 - Prob. 33ECh. 1.5 - Prob. 34ECh. 1.5 - Prob. 35ECh. 1.5 - Prob. 36ECh. 1.5 - Prob. 37ECh. 1.5 - Prob. 38ECh. 1.5 - Prob. 39ECh. 1.5 - Prob. 40ECh. 1.6 - Prob. 1CFUCh. 1.6 - Prob. 2CFUCh. 1.6 - Prob. 3CFUCh. 1.6 - Prob. 4CFUCh. 1.6 - Prob. 5CFUCh. 1.6 - Prob. 6ECh. 1.6 - Prob. 7ECh. 1.6 - Prob. 8ECh. 1.6 - Prob. 9ECh. 1.6 - Prob. 10ECh. 1.6 - Prob. 11ECh. 1.6 - Prob. 12ECh. 1.6 - Prob. 13ECh. 1.6 - Prob. 14ECh. 1.6 - Prob. 15ECh. 1.6 - Prob. 16ECh. 1.6 - Prob. 17ECh. 1.6 - Prob. 18ECh. 1.6 - Prob. 19ECh. 1.7 - Prob. 1CFUCh. 1.7 - Prob. 2CFUCh. 1.7 - Prob. 3CFUCh. 1.7 - Prob. 4CFUCh. 1.7 - Prob. 5CFUCh. 1.7 - Prob. 6CFUCh. 1.7 - Prob. 7CFUCh. 1.7 - Prob. 8CFUCh. 1.7 - Prob. 9CFUCh. 1.7 - Prob. 10CFUCh. 1.7 - Prob. 11ECh. 1.7 - Prob. 12ECh. 1.7 - Prob. 13ECh. 1.7 - Prob. 14ECh. 1.7 - Prob. 15ECh. 1.7 - Prob. 16ECh. 1.7 - Prob. 17ECh. 1.7 - Prob. 18ECh. 1.7 - Prob. 19ECh. 1.7 - Prob. 20ECh. 1.7 - Prob. 21ECh. 1.7 - Prob. 22ECh. 1.7 - Prob. 23ECh. 1.7 - Prob. 24ECh. 1.7 - Prob. 25ECh. 1.7 - Prob. 26ECh. 1.7 - Prob. 27ECh. 1.7 - Prob. 28ECh. 1.7 - Prob. 29ECh. 1.7 - Prob. 30ECh. 1.7 - Prob. 31ECh. 1.7 - Prob. 32ECh. 1.7 - Prob. 33ECh. 1.7 - Prob. 34ECh. 1.7 - Prob. 35ECh. 1.7 - Prob. 36ECh. 1.7 - Prob. 37ECh. 1.8 - Prob. 1CFUCh. 1.8 - Prob. 2CFUCh. 1.8 - Prob. 3CFUCh. 1.8 - Prob. 4CFUCh. 1.8 - Prob. 5CFUCh. 1.8 - Prob. 6CFUCh. 1.8 - Prob. 7CFUCh. 1.8 - Prob. 8CFUCh. 1.8 - Prob. 9ECh. 1.8 - Prob. 10ECh. 1.8 - Prob. 11ECh. 1.8 - Prob. 12ECh. 1.8 - Prob. 13ECh. 1.8 - Prob. 14ECh. 1.8 - Prob. 15ECh. 1.8 - Prob. 16ECh. 1.8 - Prob. 17ECh. 1.8 - Prob. 18ECh. 1.8 - Prob. 19ECh. 1.8 - Prob. 20ECh. 1.8 - Prob. 21ECh. 1.8 - Prob. 22ECh. 1.8 - Prob. 23ECh. 1.8 - Prob. 24ECh. 1.8 - Prob. 25ECh. 1.8 - Prob. 26ECh. 1.8 - Prob. 27ECh. 1.8 - Prob. 28ECh. 1.8 - Prob. 29ECh. 1.8 - Prob. 30ECh. 1.8 - Prob. 31ECh. 1.8 - Prob. 32ECh. 1 - Prob. 1SGACh. 1 - Prob. 2SGACh. 1 - Prob. 3SGACh. 1 - Prob. 4SGACh. 1 - Prob. 5SGACh. 1 - Prob. 6SGACh. 1 - Prob. 7SGACh. 1 - Prob. 8SGACh. 1 - Prob. 9SGACh. 1 - Prob. 10SGACh. 1 - Prob. 11SGACh. 1 - Prob. 12SGACh. 1 - Prob. 13SGACh. 1 - Prob. 14SGACh. 1 - Prob. 15SGACh. 1 - Prob. 16SGACh. 1 - Prob. 17SGACh. 1 - Prob. 18SGACh. 1 - Prob. 19SGACh. 1 - Prob. 20SGACh. 1 - Prob. 21SGACh. 1 - Prob. 22SGACh. 1 - Prob. 23SGACh. 1 - Prob. 24SGACh. 1 - Prob. 25SGACh. 1 - Prob. 26SGACh. 1 - Prob. 27SGACh. 1 - Prob. 28SGACh. 1 - Prob. 29SGACh. 1 - Prob. 30SGACh. 1 - Prob. 31SGACh. 1 - Prob. 32SGACh. 1 - Prob. 33SGACh. 1 - Prob. 34SGACh. 1 - Prob. 35SGACh. 1 - Prob. 36SGACh. 1 - Prob. 37SGACh. 1 - Prob. 38SGACh. 1 - Prob. 39SGACh. 1 - Prob. 40SGACh. 1 - Prob. 41SGACh. 1 - Prob. 42SGACh. 1 - Prob. 43SGACh. 1 - Prob. 44SGACh. 1 - Prob. 45SGACh. 1 - Prob. 46SGACh. 1 - Prob. 47SGACh. 1 - Prob. 48SGACh. 1 - Prob. 49SGACh. 1 - Prob. 50SGACh. 1 - Prob. 51SGACh. 1 - Prob. 52SGACh. 1 - Prob. 53SGACh. 1 - Prob. 54SGACh. 1 - Prob. 55SGACh. 1 - Prob. 56SGACh. 1 - Prob. 57SGACh. 1 - Prob. 58SGACh. 1 - Prob. 59SGACh. 1 - Prob. 60SGACh. 1 - Prob. 61SGACh. 1 - Prob. 62SGACh. 1 - Prob. 63SGACh. 1 - Prob. 64SGACh. 1 - Prob. 65SGACh. 1 - Prob. 66SGACh. 1 - Prob. 67SGACh. 1 - Prob. 68SGACh. 1 - Prob. 69SGACh. 1 - Prob. 1SAPCh. 1 - Prob. 2SAPCh. 1 - Prob. 3SAPCh. 1 - Prob. 4SAPCh. 1 - Prob. 5SAPCh. 1 - Prob. 6SAPCh. 1 - Prob. 7SAPCh. 1 - Prob. 8SAPCh. 1 - Prob. 9SAPCh. 1 - Prob. 10SAP
Additional Math Textbook Solutions
Find more solutions based on key concepts
A categorical variable has three categories, with the following frequencies of occurrence: a. Compute the perce...
Basic Business Statistics, Student Value Edition
Limits at infinity Evaluate the following limits. 11. limcos2
Calculus: Early Transcendentals (2nd Edition)
At what points are the functions in Exercises 13–32 continuous?
29.
University Calculus: Early Transcendentals (4th Edition)
Twenty five people, consisting of 15 women and 10 men are lined up in a random order. Find the probability that...
A First Course in Probability (10th Edition)
Views on Capital Punishment Use the data given in Exercise 7.23. Make the two given tables into one table by co...
Introductory Statistics
TRY IT YOURSELF 1
Find the mean of the points scored by the 51 winning teams listed on page 39.
Elementary Statistics: Picturing the World (7th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.Similar questions
- Each of the following statements is an attempt to show that a given series is convergent or divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement, enter C (for "correct") if the argument is valid, or enter | (for "incorrect") if any part of the argument is flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you must enter I.) ☐ 1. For all n > 1, seriesΣ In(n) In(n) converges. 2, 1, arctan(n) the series arctan(n) n³ ☐ 4. For all n > 1, 123 converges. 1 n ln(n) series In(n) diverges. 2n . and the seriesΣconverges, so by the Comparison Test, 2, 3, and the series converges, so by the Comparison Test, the series-3 1 converges. ☐ 6. For all n > 2, In(n) >, and the series Σ converges, so by the Comparison Test, the seriesΣ In(n) converges.arrow_forwardInstructions. "I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."arrow_forwardBoth in images okk. Instructions. "I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."arrow_forward
- Question 1: If a barometer were built using oil (p = 0.92 g/cm³) instead of mercury (p = 13.6 g/cm³), would the column of oil be higher than, lower than, or the same as the column of mercury at 1.00 atm? If the level is different, by what factor? Explain. (5 pts) Solution: A barometer works based on the principle that the pressure exerted by the liquid column balances atmospheric pressure. The pressure is given by: P = pgh Since the atmospheric pressure remains constant (P = 1.00 atm), the height of the liquid column is inversely proportional to its density: Step 1: Given Data PHg hol=hgx Poil • Density of mercury: PHg = 13.6 g/cm³ Density of oil: Poil = 0.92 g/cm³ • Standard height of mercury at 1.00 atm: hμg Step 2: Compute Height of Oil = 760 mm = 0.760 m 13.6 hoil = 0.760 x 0.92 hoil = 0.760 × 14.78 hoil = 11.23 m Step 3: Compare Heights Since oil is less dense than mercury, the column of oil must be much taller than that of mercury. The factor by which it is taller is: Final…arrow_forwardQuestion 3: A sealed flask at room temperature contains a mixture of neon (Ne) and nitrogen (N2) gases. Ne has a mass of 3.25 g and exerts a pressure of 48.2 torr. . N2 contributes a pressure of 142 torr. • What is the mass of the N2 in the flask? • Atomic mass of Ne = 20.1797 g/mol • Atomic mass of N = 14.0067 g/mol Solution: We will use the Ideal Gas Law to determine the number of moles of each gas and calculate the mass of N2. PV = nRT where: • P = total pressure • V volume of the flask (same for both gases) n = number of moles of gas • R 0.0821 L atm/mol K • T = Room temperature (assume 298 K) Since both gases are in the same flask, their partial pressures correspond to their mole fractions. Step 1: Convert Pressures to Atmospheres 48.2 PNe = 0.0634 atm 760 142 PN2 = = 0.1868 atm 760 Step 2: Determine Moles of Ne nNe = mass molar mass 3.25 nNe 20.1797 nne 0.1611 mol Step 3: Use Partial Pressure Ratio to Find narrow_forward"I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."arrow_forward
- 3.12 (B). A horizontal beam AB is 4 m long and of constant flexural rigidity. It is rigidly built-in at the left-hand end A and simply supported on a non-yielding support at the right-hand end B. The beam carries Uniformly distributed vertical loading of 18 kN/m over its whole length, together with a vertical downward load of 10KN at 2.5 m from the end A. Sketch the S.F. and B.M. diagrams for the beam, indicating all main values. Cl. Struct. E.] CS.F. 45,10,376 KN, B.M. 186, +36.15 kNm.7arrow_forwardQize f(x) = x + 2x2 - 2 x² + 4x²² - Solve the equation using Newton Raphsonarrow_forward-b±√√b2-4ac 2a @4x²-12x+9=0 27 de febrero de 2025 -b±√√b2-4ac 2a ⑥2x²-4x-1=0 a = 4 b=-12 c=9 a = 2 b = 9 c = \ x=-42±√(2-4 (4) (9) 2(4)) X = (12) ±√44)-(360) 2(108) x = ±√ X = =±√√²-4(2) (1) 2() X = ±√ + X = X = + X₁ = = X₁ = X₁ = + X₁ = = =arrow_forward
- 3.9 (A/B). A beam ABCDE, with A on the left, is 7 m long and is simply supported at Band E. The lengths of the various portions are AB 1-5m, BC = 1-5m, CD = 1 m and DE : 3 m. There is a uniformly distributed load of 15kN/m between B and a point 2m to the right of B and concentrated loads of 20 KN act at 4 and 0 with one of 50 KN at C. (a) Draw the S.F. diagrams and hence determine the position from A at which the S.F. is zero. (b) Determine the value of the B.M. at this point. (c) Sketch the B.M. diagram approximately to scale, quoting the principal values. [3.32 m, 69.8 KNm, 0, 30, 69.1, 68.1, 0 kNm.]arrow_forward4. Verify that V X (aẢ) = (Va) XẢ + aV X Ả where Ả = xyz(x + y + 2) A and a = 3xy + 4zx by carrying out the detailed differentiations.arrow_forward3. For each of the arrow or quiver graphs shown below, determine analytically V°C and V X Č. From these analytical solutions, identify the extrema (+/-) and plot these points on the arrow graph. (a) C = −✰CosxSiny + ŷSinxCosy -π<ׂу<π Ty (b) C = −xSin2y + ŷCos2y x, y<π -π< (c) C = −xCosx + ŷSiny -π< x, y < πarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage Learning
Thomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSON
Calculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. Freeman
Calculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning
Calculus: Early Transcendentals
Calculus
ISBN:9781285741550
Author:James Stewart
Publisher:Cengage Learning
Thomas' Calculus (14th Edition)
Calculus
ISBN:9780134438986
Author:Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:9780134763644
Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:PEARSON
Calculus: Early Transcendentals
Calculus
ISBN:9781319050740
Author:Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:W. H. Freeman
Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
Evaluating Indefinite Integrals; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-xHA2RjVkwY;License: Standard YouTube License, CC-BY
Calculus - Lesson 16 | Indefinite and Definite Integrals | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=bMnMzNKL9Ks;License: Standard YouTube License, CC-BY