Chapter 1, Problem 16SGA

To determine

To find: $k\left(4c\right)$

Answer to Problem 16SGA

  $16c^2+8c-4$

Explanation of Solution

Given information:

  $k\left(x\right)=x^2+2x-4$

Calculation:

Put $x=4c$ in $k\left(x\right)$ and evaluated as follows:

  $\begin{array}{c}k\left(x\right)=x^2+2x-4\\ k\left(4c\right)={\left(4c\right)}^2+2\left(4c\right)-4\\ =16c^2+8c-4\end{array}$

Thus, the value of $k\left(4c\right)$ is $16c^2+8c-4$ .