Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
1st Edition
ISBN: 9780078682278
Author: McGraw-Hill, Berchie Holliday
Publisher: Glencoe/McGraw-Hill
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 1.1, Problem 52E
a
To determine
To find: set of ordered pairs, domain and range of the relation from the provided data.
a
Expert Solution
Answer to Problem 52E
Relation=
Range=
Explanation of Solution
Given information:
| University | Number of students applied | Number of students attending |
| Auburn University | 13264 | 4184 |
| University of California-Davis | 27954 | 4412 |
| University of Illinois-Urbana-Champaign | 21484 | 6366 |
| University of Maryland-College Park | 23117 | 3912 |
| State University of New York-Stony Brook | 16849 | 2145 |
| The Ohio State university | 19563 | 5982 |
| Texas A&M University | 17284 | 6949 |
Calculation:
Let the number of students applied be x and the number of students attending be y. So the table for variables will be as follows:
| Number of students applied (x) | Number of students attending (y) |
| 13264 | 4184 |
| 27954 | 4412 |
| 21484 | 6366 |
| 23117 | 3912 |
| 16849 | 2145 |
| 19563 | 5982 |
| 17284 | 6949 |
From the table, the set of ordered pairs of the relation in (x, y) is as follows:
Since all the possible values of x is a domain. So, the domain value is shown below.
All the possible values of y represent the range. So, the range is as follows:
b
To determine
To represent: the graphical relation.
b
Expert Solution
Answer to Problem 52E
Explanation of Solution
Given information:
| Number of students applied (x) | Number of students attending (y) |
| 13264 | 4184 |
| 27954 | 4412 |
| 21484 | 6366 |
| 23117 | 3912 |
| 16849 | 2145 |
| 19563 | 5982 |
| 17284 | 6949 |
Calculation:
From the table, the set of ordered pairs of the relation in (x, y) is as follows:
Plotting these values on graph we get a relation as follows:
c.
To determine
whether the relation is a function along with an explanation.
c.
Expert Solution
Answer to Problem 52E
This relation is a function because no two set of ordered pairs have same first element.
Explanation of Solution
Given information:
| University | Number of students applied | Number of students attending |
| Auburn University | 13264 | 4184 |
| University of California-Davis | 27954 | 4412 |
| University of Illinois-Urbana-Champaign | 21484 | 6366 |
| University of Maryland-College Park | 23117 | 3912 |
| State University of New York-Stony Brook | 16849 | 2145 |
| The Ohio State university | 19563 | 5982 |
| Texas A&M University | 17284 | 6949 |
Calculation:
From the table, the set of ordered pairs of the relation in (x, y) is as follows:
Since, the no two set of ordered pairs have same first element. Hence, this relation is a function.
Chapter 1 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Ch. 1.1 - Prob. 1CFUCh. 1.1 - Prob. 2CFUCh. 1.1 - Prob. 3CFUCh. 1.1 - Prob. 4CFUCh. 1.1 - Prob. 5CFUCh. 1.1 - Prob. 6CFUCh. 1.1 - Prob. 7CFUCh. 1.1 - Prob. 8CFUCh. 1.1 - Prob. 9CFUCh. 1.1 - Prob. 10CFU
Ch. 1.1 - Prob. 11CFUCh. 1.1 - Prob. 12CFUCh. 1.1 - Prob. 13CFUCh. 1.1 - Prob. 14CFUCh. 1.1 - Prob. 15CFUCh. 1.1 - Prob. 16CFUCh. 1.1 - Prob. 17ECh. 1.1 - Prob. 18ECh. 1.1 - Prob. 19ECh. 1.1 - Prob. 20ECh. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.1 - Prob. 37ECh. 1.1 - Prob. 38ECh. 1.1 - Prob. 39ECh. 1.1 - Prob. 40ECh. 1.1 - Prob. 41ECh. 1.1 - Prob. 42ECh. 1.1 - Prob. 43ECh. 1.1 - Prob. 44ECh. 1.1 - Prob. 45ECh. 1.1 - Prob. 46ECh. 1.1 - Prob. 47ECh. 1.1 - Prob. 48ECh. 1.1 - Prob. 49ECh. 1.1 - Prob. 50ECh. 1.1 - Prob. 51ECh. 1.1 - Prob. 52ECh. 1.1 - Prob. 53ECh. 1.1 - Prob. 54ECh. 1.1 - Prob. 55ECh. 1.1 - Prob. 56ECh. 1.1 - Prob. 57ECh. 1.2 - Prob. 1GCECh. 1.2 - Prob. 2GCECh. 1.2 - Prob. 3GCECh. 1.2 - Prob. 4GCECh. 1.2 - Prob. 5GCECh. 1.2 - Prob. 1CFUCh. 1.2 - Prob. 2CFUCh. 1.2 - Prob. 3CFUCh. 1.2 - Prob. 4CFUCh. 1.2 - Prob. 5CFUCh. 1.2 - Prob. 6CFUCh. 1.2 - Prob. 7CFUCh. 1.2 - Prob. 8CFUCh. 1.2 - Prob. 9CFUCh. 1.2 - Prob. 10CFUCh. 1.2 - Prob. 11ECh. 1.2 - Prob. 12ECh. 1.2 - Prob. 13ECh. 1.2 - Prob. 14ECh. 1.2 - Prob. 15ECh. 1.2 - Prob. 16ECh. 1.2 - Prob. 17ECh. 1.2 - Prob. 18ECh. 1.2 - Prob. 19ECh. 1.2 - Prob. 20ECh. 1.2 - Prob. 21ECh. 1.2 - Prob. 22ECh. 1.2 - Prob. 23ECh. 1.2 - Prob. 24ECh. 1.2 - Prob. 25ECh. 1.2 - Prob. 26ECh. 1.2 - Prob. 27ECh. 1.2 - Prob. 28ECh. 1.2 - Prob. 29ECh. 1.2 - Prob. 30ECh. 1.2 - Prob. 31ECh. 1.2 - Prob. 32ECh. 1.2 - Prob. 33ECh. 1.2 - Prob. 34ECh. 1.2 - Prob. 35ECh. 1.2 - Prob. 36ECh. 1.2 - Prob. 37ECh. 1.2 - Prob. 38ECh. 1.2 - Prob. 39ECh. 1.3 - Prob. 1CFUCh. 1.3 - Prob. 2CFUCh. 1.3 - Prob. 3CFUCh. 1.3 - Prob. 4CFUCh. 1.3 - Prob. 5CFUCh. 1.3 - Prob. 6CFUCh. 1.3 - Prob. 7CFUCh. 1.3 - Prob. 8CFUCh. 1.3 - Prob. 9CFUCh. 1.3 - Prob. 10CFUCh. 1.3 - Prob. 11CFUCh. 1.3 - Prob. 12ECh. 1.3 - Prob. 13ECh. 1.3 - Prob. 14ECh. 1.3 - Prob. 15ECh. 1.3 - Prob. 16ECh. 1.3 - Prob. 17ECh. 1.3 - Prob. 18ECh. 1.3 - Prob. 19ECh. 1.3 - Prob. 20ECh. 1.3 - Prob. 21ECh. 1.3 - Prob. 22ECh. 1.3 - Prob. 23ECh. 1.3 - Prob. 24ECh. 1.3 - Prob. 25ECh. 1.3 - Prob. 26ECh. 1.3 - Prob. 27ECh. 1.3 - Prob. 28ECh. 1.3 - Prob. 29ECh. 1.3 - Prob. 30ECh. 1.3 - Prob. 31ECh. 1.3 - Prob. 32ECh. 1.3 - Prob. 33ECh. 1.3 - Prob. 34ECh. 1.3 - Prob. 35ECh. 1.3 - Prob. 36ECh. 1.3 - Prob. 37ECh. 1.3 - Prob. 38ECh. 1.3 - Prob. 39ECh. 1.3 - Prob. 40ECh. 1.3 - Prob. 41ECh. 1.3 - Prob. 42ECh. 1.3 - Prob. 43ECh. 1.3 - Prob. 44ECh. 1.3 - Prob. 45ECh. 1.3 - Prob. 46ECh. 1.3B - Prob. 1GCECh. 1.3B - Prob. 2GCECh. 1.3B - Prob. 3GCECh. 1.4 - Prob. 1CFUCh. 1.4 - Prob. 2CFUCh. 1.4 - Prob. 3CFUCh. 1.4 - Prob. 4CFUCh. 1.4 - Prob. 5CFUCh. 1.4 - Prob. 6CFUCh. 1.4 - Prob. 7CFUCh. 1.4 - Prob. 8CFUCh. 1.4 - Prob. 9CFUCh. 1.4 - Prob. 10CFUCh. 1.4 - Prob. 11ECh. 1.4 - Prob. 12ECh. 1.4 - Prob. 13ECh. 1.4 - Prob. 14ECh. 1.4 - Prob. 15ECh. 1.4 - Prob. 16ECh. 1.4 - Prob. 17ECh. 1.4 - Prob. 18ECh. 1.4 - Prob. 19ECh. 1.4 - Prob. 20ECh. 1.4 - Prob. 21ECh. 1.4 - Prob. 22ECh. 1.4 - Prob. 23ECh. 1.4 - Prob. 24ECh. 1.4 - Prob. 25ECh. 1.4 - Prob. 26ECh. 1.4 - Prob. 27ECh. 1.4 - Prob. 28ECh. 1.4 - Prob. 29ECh. 1.4 - Prob. 30ECh. 1.4 - Prob. 31ECh. 1.4 - Prob. 32ECh. 1.4 - Prob. 33ECh. 1.4 - Prob. 34ECh. 1.4 - Prob. 35ECh. 1.4 - Prob. 1MCQCh. 1.4 - Prob. 2MCQCh. 1.4 - Prob. 3MCQCh. 1.4 - Prob. 4MCQCh. 1.4 - Prob. 5MCQCh. 1.4 - Prob. 6MCQCh. 1.4 - Prob. 7MCQCh. 1.4 - Prob. 8MCQCh. 1.4 - Prob. 9MCQCh. 1.4 - Prob. 10MCQCh. 1.5 - Prob. 1CFUCh. 1.5 - Prob. 2CFUCh. 1.5 - Prob. 3CFUCh. 1.5 - Prob. 4CFUCh. 1.5 - Prob. 5CFUCh. 1.5 - Prob. 6CFUCh. 1.5 - Prob. 7CFUCh. 1.5 - Prob. 8CFUCh. 1.5 - Prob. 9CFUCh. 1.5 - Prob. 10CFUCh. 1.5 - Prob. 11CFUCh. 1.5 - Prob. 12ECh. 1.5 - Prob. 13ECh. 1.5 - Prob. 14ECh. 1.5 - Prob. 15ECh. 1.5 - Prob. 16ECh. 1.5 - Prob. 17ECh. 1.5 - Prob. 18ECh. 1.5 - Prob. 19ECh. 1.5 - Prob. 20ECh. 1.5 - Prob. 21ECh. 1.5 - Prob. 22ECh. 1.5 - Prob. 23ECh. 1.5 - Prob. 24ECh. 1.5 - Prob. 25ECh. 1.5 - Prob. 26ECh. 1.5 - Prob. 27ECh. 1.5 - Prob. 28ECh. 1.5 - Prob. 29ECh. 1.5 - Prob. 30ECh. 1.5 - Prob. 31ECh. 1.5 - Prob. 32ECh. 1.5 - Prob. 33ECh. 1.5 - Prob. 34ECh. 1.5 - Prob. 35ECh. 1.5 - Prob. 36ECh. 1.5 - Prob. 37ECh. 1.5 - Prob. 38ECh. 1.5 - Prob. 39ECh. 1.5 - Prob. 40ECh. 1.6 - Prob. 1CFUCh. 1.6 - Prob. 2CFUCh. 1.6 - Prob. 3CFUCh. 1.6 - Prob. 4CFUCh. 1.6 - Prob. 5CFUCh. 1.6 - Prob. 6ECh. 1.6 - Prob. 7ECh. 1.6 - Prob. 8ECh. 1.6 - Prob. 9ECh. 1.6 - Prob. 10ECh. 1.6 - Prob. 11ECh. 1.6 - Prob. 12ECh. 1.6 - Prob. 13ECh. 1.6 - Prob. 14ECh. 1.6 - Prob. 15ECh. 1.6 - Prob. 16ECh. 1.6 - Prob. 17ECh. 1.6 - Prob. 18ECh. 1.6 - Prob. 19ECh. 1.7 - Prob. 1CFUCh. 1.7 - Prob. 2CFUCh. 1.7 - Prob. 3CFUCh. 1.7 - Prob. 4CFUCh. 1.7 - Prob. 5CFUCh. 1.7 - Prob. 6CFUCh. 1.7 - Prob. 7CFUCh. 1.7 - Prob. 8CFUCh. 1.7 - Prob. 9CFUCh. 1.7 - Prob. 10CFUCh. 1.7 - Prob. 11ECh. 1.7 - Prob. 12ECh. 1.7 - Prob. 13ECh. 1.7 - Prob. 14ECh. 1.7 - Prob. 15ECh. 1.7 - Prob. 16ECh. 1.7 - Prob. 17ECh. 1.7 - Prob. 18ECh. 1.7 - Prob. 19ECh. 1.7 - Prob. 20ECh. 1.7 - Prob. 21ECh. 1.7 - Prob. 22ECh. 1.7 - Prob. 23ECh. 1.7 - Prob. 24ECh. 1.7 - Prob. 25ECh. 1.7 - Prob. 26ECh. 1.7 - Prob. 27ECh. 1.7 - Prob. 28ECh. 1.7 - Prob. 29ECh. 1.7 - Prob. 30ECh. 1.7 - Prob. 31ECh. 1.7 - Prob. 32ECh. 1.7 - Prob. 33ECh. 1.7 - Prob. 34ECh. 1.7 - Prob. 35ECh. 1.7 - Prob. 36ECh. 1.7 - Prob. 37ECh. 1.8 - Prob. 1CFUCh. 1.8 - Prob. 2CFUCh. 1.8 - Prob. 3CFUCh. 1.8 - Prob. 4CFUCh. 1.8 - Prob. 5CFUCh. 1.8 - Prob. 6CFUCh. 1.8 - Prob. 7CFUCh. 1.8 - Prob. 8CFUCh. 1.8 - Prob. 9ECh. 1.8 - Prob. 10ECh. 1.8 - Prob. 11ECh. 1.8 - Prob. 12ECh. 1.8 - Prob. 13ECh. 1.8 - Prob. 14ECh. 1.8 - Prob. 15ECh. 1.8 - Prob. 16ECh. 1.8 - Prob. 17ECh. 1.8 - Prob. 18ECh. 1.8 - Prob. 19ECh. 1.8 - Prob. 20ECh. 1.8 - Prob. 21ECh. 1.8 - Prob. 22ECh. 1.8 - Prob. 23ECh. 1.8 - Prob. 24ECh. 1.8 - Prob. 25ECh. 1.8 - Prob. 26ECh. 1.8 - Prob. 27ECh. 1.8 - Prob. 28ECh. 1.8 - Prob. 29ECh. 1.8 - Prob. 30ECh. 1.8 - Prob. 31ECh. 1.8 - Prob. 32ECh. 1 - Prob. 1SGACh. 1 - Prob. 2SGACh. 1 - Prob. 3SGACh. 1 - Prob. 4SGACh. 1 - Prob. 5SGACh. 1 - Prob. 6SGACh. 1 - Prob. 7SGACh. 1 - Prob. 8SGACh. 1 - Prob. 9SGACh. 1 - Prob. 10SGACh. 1 - Prob. 11SGACh. 1 - Prob. 12SGACh. 1 - Prob. 13SGACh. 1 - Prob. 14SGACh. 1 - Prob. 15SGACh. 1 - Prob. 16SGACh. 1 - Prob. 17SGACh. 1 - Prob. 18SGACh. 1 - Prob. 19SGACh. 1 - Prob. 20SGACh. 1 - Prob. 21SGACh. 1 - Prob. 22SGACh. 1 - Prob. 23SGACh. 1 - Prob. 24SGACh. 1 - Prob. 25SGACh. 1 - Prob. 26SGACh. 1 - Prob. 27SGACh. 1 - Prob. 28SGACh. 1 - Prob. 29SGACh. 1 - Prob. 30SGACh. 1 - Prob. 31SGACh. 1 - Prob. 32SGACh. 1 - Prob. 33SGACh. 1 - Prob. 34SGACh. 1 - Prob. 35SGACh. 1 - Prob. 36SGACh. 1 - Prob. 37SGACh. 1 - Prob. 38SGACh. 1 - Prob. 39SGACh. 1 - Prob. 40SGACh. 1 - Prob. 41SGACh. 1 - Prob. 42SGACh. 1 - Prob. 43SGACh. 1 - Prob. 44SGACh. 1 - Prob. 45SGACh. 1 - Prob. 46SGACh. 1 - Prob. 47SGACh. 1 - Prob. 48SGACh. 1 - Prob. 49SGACh. 1 - Prob. 50SGACh. 1 - Prob. 51SGACh. 1 - Prob. 52SGACh. 1 - Prob. 53SGACh. 1 - Prob. 54SGACh. 1 - Prob. 55SGACh. 1 - Prob. 56SGACh. 1 - Prob. 57SGACh. 1 - Prob. 58SGACh. 1 - Prob. 59SGACh. 1 - Prob. 60SGACh. 1 - Prob. 61SGACh. 1 - Prob. 62SGACh. 1 - Prob. 63SGACh. 1 - Prob. 64SGACh. 1 - Prob. 65SGACh. 1 - Prob. 66SGACh. 1 - Prob. 67SGACh. 1 - Prob. 68SGACh. 1 - Prob. 69SGACh. 1 - Prob. 1SAPCh. 1 - Prob. 2SAPCh. 1 - Prob. 3SAPCh. 1 - Prob. 4SAPCh. 1 - Prob. 5SAPCh. 1 - Prob. 6SAPCh. 1 - Prob. 7SAPCh. 1 - Prob. 8SAPCh. 1 - Prob. 9SAPCh. 1 - Prob. 10SAP
Additional Math Textbook Solutions
Find more solutions based on key concepts
a. Fill in the missing numbers in the following factor tree. b. How could you find the top numbers without find...
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
CHECK POINT 1 Write a word description of the set L = {a, b, c, d, e, f}.
Thinking Mathematically (6th Edition)
Completing the square Evaluate the following integrals. 59. dxx2+6x+18
Calculus: Early Transcendentals (2nd Edition)
The following set of data is from sample of n=5: a. Compute the mean, median, and mode. b. Compute the range, v...
Basic Business Statistics, Student Value Edition
4. Annual Incomes Annual incomes are known to have a distribution that is skewed to the right instead of being ...
Elementary Statistics (13th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.Similar questions
- Can you answer this question and give step by step and why and how to get it. Can you write it (numerical method)arrow_forwardCan you answer this question and give step by step and why and how to get it. Can you write it (numerical method)arrow_forwardThere are three options for investing $1150. The first earns 10% compounded annually, the second earns 10% compounded quarterly, and the third earns 10% compounded continuously. Find equations that model each investment growth and use a graphing utility to graph each model in the same viewing window over a 20-year period. Use the graph to determine which investment yields the highest return after 20 years. What are the differences in earnings among the three investment? STEP 1: The formula for compound interest is A = nt = P(1 + − − ) n², where n is the number of compoundings per year, t is the number of years, r is the interest rate, P is the principal, and A is the amount (balance) after t years. For continuous compounding, the formula reduces to A = Pert Find r and n for each model, and use these values to write A in terms of t for each case. Annual Model r=0.10 A = Y(t) = 1150 (1.10)* n = 1 Quarterly Model r = 0.10 n = 4 A = Q(t) = 1150(1.025) 4t Continuous Model r=0.10 A = C(t) =…arrow_forward
- Use a graphing utility to find the point of intersection, if any, of the graphs of the functions. Round your result to three decimal places. (Enter NONE in any unused answer blanks.) y = 100e0.01x (x, y) = y = 11,250 ×arrow_forward5. For the function y-x³-3x²-1, use derivatives to: (a) determine the intervals of increase and decrease. (b) determine the local (relative) maxima and minima. (e) determine the intervals of concavity. (d) determine the points of inflection. (e) sketch the graph with the above information indicated on the graph.arrow_forwardCan you solve this 2 question numerical methodarrow_forward
- 1. Estimate the area under the graph of f(x)-25-x from x=0 to x=5 using 5 approximating rectangles Using: (A) right endpoints. (B) left endpoints.arrow_forward9. Use fundamental theorem of calculus to find the derivative d a) *dt sin(x) b)(x)√1-2 dtarrow_forward3. Evaluate the definite integral: a) √66x²+8dx b) x dx c) f*(2e* - 2)dx d) √√9-x² e) (2-5x)dx f) cos(x)dx 8)²₁₂√4-x2 h) f7dx i) f² 6xdx j) ²₂(4x+3)dxarrow_forward
- 2. Consider the integral √(2x+1)dx (a) Find the Riemann sum for this integral using right endpoints and n-4. (b) Find the Riemann sum for this same integral, using left endpoints and n=4arrow_forwardProblem 11 (a) A tank is discharging water through an orifice at a depth of T meter below the surface of the water whose area is A m². The following are the values of a for the corresponding values of A: A 1.257 1.390 x 1.50 1.65 1.520 1.650 1.809 1.962 2.123 2.295 2.462|2.650 1.80 1.95 2.10 2.25 2.40 2.55 2.70 2.85 Using the formula -3.0 (0.018)T = dx. calculate T, the time in seconds for the level of the water to drop from 3.0 m to 1.5 m above the orifice. (b) The velocity of a train which starts from rest is given by the fol- lowing table, the time being reckoned in minutes from the start and the speed in km/hour: | † (minutes) |2|4 6 8 10 12 14 16 18 20 v (km/hr) 16 28.8 40 46.4 51.2 32.0 17.6 8 3.2 0 Estimate approximately the total distance ran in 20 minutes.arrow_forwardX Solve numerically: = 0,95 In xarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage Learning
Thomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSON
Calculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. Freeman
Calculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning
Calculus: Early Transcendentals
Calculus
ISBN:9781285741550
Author:James Stewart
Publisher:Cengage Learning
Thomas' Calculus (14th Edition)
Calculus
ISBN:9780134438986
Author:Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:9780134763644
Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:PEARSON
Calculus: Early Transcendentals
Calculus
ISBN:9781319050740
Author:Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:W. H. Freeman
Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
What is a Relation? | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=hV1_wvsdJCE;License: Standard YouTube License, CC-BY
RELATIONS-DOMAIN, RANGE AND CO-DOMAIN (RELATIONS AND FUNCTIONS CBSE/ ISC MATHS); Author: Neha Agrawal Mathematically Inclined;https://www.youtube.com/watch?v=u4IQh46VoU4;License: Standard YouTube License, CC-BY