
Concept explainers
a.
To find: equations of two lines that satisfy the given condition.
a.

Answer to Problem 30E
Explanation of Solution
Given information:
Lines are perpendicular to each other. One line is vertical.
Calculation:
Since on vertical line is always perpendicular to the horizontal line. Then according to the given condition, the other line must be horizontal in nature.
The slope of vertical line is negative undefined, and y- intercept is zero.
The slope of horizontal line is zero and x- intercept is zero.
Therefore, the equations for vertical and horizontal lines can be as follows:
b.
To find: equations of two lines that satisfy the given condition.
b.

Answer to Problem 30E
Explanation of Solution
Given information:
Lines are parallel to each other and neither has a y- intercept.
Calculation:
Since both the lines are parallel and do not have y- intercept, then both the lines must vertical.
Therefore, the equations for the parallel lines having no y- intercept can be as follows:
Chapter 1 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Additional Math Textbook Solutions
Calculus: Early Transcendentals (2nd Edition)
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Basic Business Statistics, Student Value Edition
Algebra and Trigonometry (6th Edition)
College Algebra with Modeling & Visualization (5th Edition)
- A tank holds a 135 gal solution of water and salt. Initially, the solution contains 21 lb of salt. A salt solution with a concentration of 3 lb of salt per gal begins flowing into the tank at the rate of 3 gal per minute. The solution in the tank also begins flowing out at a rate of 3 gal per minute. Let y be the amount of salt present in the tank at time t. (a) Find an expression for the amount of salt in the tank at any time. (b) How much salt is present after 51 minutes? (c) As time increases, what happens to the salt concentration?arrow_forwardSolve please and thanks!arrow_forwardSolve please and thanks!arrow_forward
- The graph of the function f in the figure below consists of line segments and a semicircle. Let g be the function given by x 9(x) = * f(t)dt. Determine all values of r, if any, where g has a relative minimum on the open interval (-9, 9). y 8 7 6 5 4 32 1 Graph of f x -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10 -1 -2 -3 -4 -5 -6 678 -7 -8arrow_forwardSolve pleasearrow_forwardA particle moves along the x-axis for 0 < t < 18 such that its velocity is given by the graph shown below. Find the total distance traveled by the particle during the time interval 4 ≤ t ≤ 8. 8 y 7 6 5 4 32 1 6 7 -1 1 2 3 4 5 -1 -2 -3 -4 56 -6 -8 8 00 Graph of v(t) x 9 10 11 12 13 14 15 16 17 18 19arrow_forward
- Using the Chain rule please and thank youarrow_forward10. [-/3 Points] DETAILS MY NOTES SESSCALCET2 7.2.047. Consider the following. aR- br (a) Set up an integral for the volume a solid torus (the donut-shaped solid shown in the figure) with radii br and aR. (Let a 8 and b = 2.) = dy (b) By interpreting the integral as an area, find the volume V of the torus. V = Need Help? Read It Watch Itarrow_forwardGraph y= log(x − 1) +4 10+ 9 8 7 6 5 4 32 1 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 -1 6 7 8 9 10 -2 -3 -4 -5 -6 -7 -8 -9 -10arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





