Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

1st Edition

ISBN: 9780078682278

Author: McGraw-Hill, Berchie Holliday

Publisher: Glencoe/McGraw-Hill

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Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Question

Chapter 1.4, Problem 25E

To determine

To find: equation for time to acclimate to an altitude.

Expert Solution

Answer to Problem 25E

t=0.0005f−1.5

Explanation of Solution

Given information:

Time to become acclimate is 2 weeks for first 7000ft, then 1 week for each additional 2000 ft.

The variables are as follows:

t=timef=altitude in feets

Calculation:

According to the given information the value of t and f is shown below.

Time (in weeks)	Altitude (in feet)
t1=2	f1=7000
t2=3	f2=9000

The equation of t with respect to f will be as follows:

t=mf+b [Slope intercept form]m=t2−t1f2−f1 [Slope equation]

Put the values of (f1,t1) and (f2,t2) in the slope equation and evaluate m as follows:

m=3−29000−7000=12000=0.0005

Now, put the value of m and (f1,t1) in the slope intercept equation and evaluate b as follows:

2=(0.0005)7000+b2=3.5+bb=2−3.5=−1.5

Now, put the value of m and b in the slope intercept form as shown below.

t=mf+bt=0.0005f−1.5

Thus, the equation is t=0.0005f−1.5 .

To determine

To find: the time taken by a person to acclimate at the given elevation/ altitude.

Expert Solution

Answer to Problem 25E

About 6 weeks

Explanation of Solution

Given information:

The variables are as follows:

t=timef=altitude in feets

The equation for time to acclimate to an altitude (evaluated in part a.) is as follows:

t=0.0005f−1.5

The given value of f is 14494 feet.

Calculation:

Put the value of f in the equation for time to acclimate to an altitude and evaluate t as follows:

t=0.0005f−1.5=0.0005(14494)−1.5=7.247−1.5=5.747≈6 weeks

Thus, the time taken to reach the given altitude is about 6 weeks.

Chapter 1.4, Problem 24E

Chapter 1.4, Problem 26E

Chapter 1 Solutions

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

Ch. 1.1 - Prob. 1CFU Ch. 1.1 - Prob. 2CFU Ch. 1.1 - Prob. 3CFU Ch. 1.1 - Prob. 4CFU Ch. 1.1 - Prob. 5CFU Ch. 1.1 - Prob. 6CFU Ch. 1.1 - Prob. 7CFU Ch. 1.1 - Prob. 8CFU Ch. 1.1 - Prob. 9CFU Ch. 1.1 - Prob. 10CFU

Ch. 1.1 - Prob. 11CFU Ch. 1.1 - Prob. 12CFU Ch. 1.1 - Prob. 13CFU Ch. 1.1 - Prob. 14CFU Ch. 1.1 - Prob. 15CFU Ch. 1.1 - Prob. 16CFU Ch. 1.1 - Prob. 17E Ch. 1.1 - Prob. 18E Ch. 1.1 - Prob. 19E Ch. 1.1 - Prob. 20E Ch. 1.1 - Prob. 21E Ch. 1.1 - Prob. 22E Ch. 1.1 - Prob. 23E Ch. 1.1 - Prob. 24E Ch. 1.1 - Prob. 25E Ch. 1.1 - Prob. 26E Ch. 1.1 - Prob. 27E Ch. 1.1 - Prob. 28E Ch. 1.1 - Prob. 29E Ch. 1.1 - Prob. 30E Ch. 1.1 - Prob. 31E Ch. 1.1 - Prob. 32E Ch. 1.1 - Prob. 33E Ch. 1.1 - Prob. 34E Ch. 1.1 - Prob. 35E Ch. 1.1 - Prob. 36E Ch. 1.1 - Prob. 37E Ch. 1.1 - Prob. 38E Ch. 1.1 - Prob. 39E Ch. 1.1 - Prob. 40E Ch. 1.1 - Prob. 41E Ch. 1.1 - Prob. 42E Ch. 1.1 - Prob. 43E Ch. 1.1 - Prob. 44E Ch. 1.1 - Prob. 45E Ch. 1.1 - Prob. 46E Ch. 1.1 - Prob. 47E Ch. 1.1 - Prob. 48E Ch. 1.1 - Prob. 49E Ch. 1.1 - Prob. 50E Ch. 1.1 - Prob. 51E Ch. 1.1 - Prob. 52E Ch. 1.1 - Prob. 53E Ch. 1.1 - Prob. 54E Ch. 1.1 - Prob. 55E Ch. 1.1 - Prob. 56E Ch. 1.1 - Prob. 57E Ch. 1.2 - Prob. 1GCE Ch. 1.2 - Prob. 2GCE Ch. 1.2 - 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