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Question 4: Consider the following reaction: SO2O2SO3 If a 25.0 mL sample of SO2 gas undergoes complete conversion to SO3 gas under identical conditions, what will be the final volume of SO3? (3 pts) Solution: Since the reaction occurs under identical temperature and pressure, the volume ratio follows the mole ratio from the balanced chemical equation. Step 1: Identify the Mole Ratios From the balanced equation: 2502+02 250% → • 2 moles of SO 2 produce 2 moles of SO3. Since gases at the same temperature and pressure occupy volumes proportional to their mole ratio, we conclude: Vo moles of SO3 = 2 = = 1 Vso moles of SO2 2 • This means 1 volume of SO2 produces 1 volume of SO3. Step 2: Use Volume Ratios Since 25.0 mL of SO 2 reacts completely, the volume of SO3 formed is: Vso3 = Vso₂ = 25.0 mL Final Answer: 25.0 mL of SO3 Question 5: A gas bubble with an initial volume of 2.5 cm³ forms at the bottom of a lake, where the pressure is 4.2 atm. Determine the volume of the bubble when it rises to the surface, where the pressure is 685 torr. Express your final answer in L. (7 pts) Solution: Since the temperature is constant, we use Boyle's Law: P₁V₁ = P2V2 Step 1: Convert Units • Initial volume: V₁ = 2.5 cm³ = 2.5 × 10-3 L • Initial pressure: P₁ = 4.2 atm • Final pressure: P₂ = 685 torr Convert P2 to atm: 1 atm P₂ = 685 x = 0.901 atm 760 torr Step 2: Solve for V₂ Rearrange Boyle's Law to solve for V2: P₁V₁ V₂ = P2 (4.2 x 2.5 x 10-3) V₂ = 0.901 0.0105 V₂ = = 0.0117 L 0.901 Final Answer: The bubble's final volume at the surface is 0.0117 L.

Question 4: Consider the following reaction: SO2O2SO3 If a 25.0 mL sample of SO2 gas undergoes complete conversion to SO3 gas under identical conditions, what will be the final volume of SO3? (3 pts) Solution: Since the reaction occurs under identical temperature and pressure, the volume ratio follows the mole ratio from the balanced chemical equation. Step 1: Identify the Mole Ratios From the balanced equation: 2502+02 250% → • 2 moles of SO 2 produce 2 moles of SO3. Since gases at the same temperature and pressure occupy volumes proportional to their mole ratio, we conclude: Vo moles of SO3 = 2 = = 1 Vso moles of SO2 2 • This means 1 volume of SO2 produces 1 volume of SO3. Step 2: Use Volume Ratios Since 25.0 mL of SO 2 reacts completely, the volume of SO3 formed is: Vso3 = Vso₂ = 25.0 mL Final Answer: 25.0 mL of SO3 Question 5: A gas bubble with an initial volume of 2.5 cm³ forms at the bottom of a lake, where the pressure is 4.2 atm. Determine the volume of the bubble when it rises to the surface, where the pressure is 685 torr. Express your final answer in L. (7 pts) Solution: Since the temperature is constant, we use Boyle's Law: P₁V₁ = P2V2 Step 1: Convert Units • Initial volume: V₁ = 2.5 cm³ = 2.5 × 10-3 L • Initial pressure: P₁ = 4.2 atm • Final pressure: P₂ = 685 torr Convert P2 to atm: 1 atm P₂ = 685 x = 0.901 atm 760 torr Step 2: Solve for V₂ Rearrange Boyle's Law to solve for V2: P₁V₁ V₂ = P2 (4.2 x 2.5 x 10-3) V₂ = 0.901 0.0105 V₂ = = 0.0117 L 0.901 Final Answer: The bubble's final volume at the surface is 0.0117 L.

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter12: Quadratic Functions
Section12.6: Solving Problems Involving Quadratic Equations
Problem 1.4E
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Question 4: Consider the following reaction: SO2O2SO3 If a 25.0 mL sample of SO2 gas undergoes complete conversion to SO3 gas under identical conditions, what will be the final volume of SO3? (3 pts) Solution: Since the reaction occurs under identical temperature and pressure, the volume ratio follows the mole ratio from the balanced chemical equation. Step 1: Identify the Mole Ratios From the balanced equation: 2502+02 250% → • 2 moles of SO 2 produce 2 moles of SO3. Since gases at the same temperature and pressure occupy volumes proportional to their mole ratio, we conclude: Vo moles of SO3 = 2 = = 1 Vso moles of SO2 2 • This means 1 volume of SO2 produces 1 volume of SO3. Step 2: Use Volume Ratios Since 25.0 mL of SO 2 reacts completely, the volume of SO3 formed is: Vso3 = Vso₂ = 25.0 mL Final Answer: 25.0 mL of SO3
Transcribed Image Text:Question 4: Consider the following reaction: SO2O2SO3 If a 25.0 mL sample of SO2 gas undergoes complete conversion to SO3 gas under identical conditions, what will be the final volume of SO3? (3 pts) Solution: Since the reaction occurs under identical temperature and pressure, the volume ratio follows the mole ratio from the balanced chemical equation. Step 1: Identify the Mole Ratios From the balanced equation: 2502+02 250% → • 2 moles of SO 2 produce 2 moles of SO3. Since gases at the same temperature and pressure occupy volumes proportional to their mole ratio, we conclude: Vo moles of SO3 = 2 = = 1 Vso moles of SO2 2 • This means 1 volume of SO2 produces 1 volume of SO3. Step 2: Use Volume Ratios Since 25.0 mL of SO 2 reacts completely, the volume of SO3 formed is: Vso3 = Vso₂ = 25.0 mL Final Answer: 25.0 mL of SO3
Question 5: A gas bubble with an initial volume of 2.5 cm³ forms at the bottom of a lake, where the pressure is 4.2 atm. Determine the volume of the bubble when it rises to the surface, where the pressure is 685 torr. Express your final answer in L. (7 pts) Solution: Since the temperature is constant, we use Boyle's Law: P₁V₁ = P2V2 Step 1: Convert Units • Initial volume: V₁ = 2.5 cm³ = 2.5 × 10-3 L • Initial pressure: P₁ = 4.2 atm • Final pressure: P₂ = 685 torr Convert P2 to atm: 1 atm P₂ = 685 x = 0.901 atm 760 torr Step 2: Solve for V₂ Rearrange Boyle's Law to solve for V2: P₁V₁ V₂ = P2 (4.2 x 2.5 x 10-3) V₂ = 0.901 0.0105 V₂ = = 0.0117 L 0.901 Final Answer: The bubble's final volume at the surface is 0.0117 L.
Transcribed Image Text:Question 5: A gas bubble with an initial volume of 2.5 cm³ forms at the bottom of a lake, where the pressure is 4.2 atm. Determine the volume of the bubble when it rises to the surface, where the pressure is 685 torr. Express your final answer in L. (7 pts) Solution: Since the temperature is constant, we use Boyle's Law: P₁V₁ = P2V2 Step 1: Convert Units • Initial volume: V₁ = 2.5 cm³ = 2.5 × 10-3 L • Initial pressure: P₁ = 4.2 atm • Final pressure: P₂ = 685 torr Convert P2 to atm: 1 atm P₂ = 685 x = 0.901 atm 760 torr Step 2: Solve for V₂ Rearrange Boyle's Law to solve for V2: P₁V₁ V₂ = P2 (4.2 x 2.5 x 10-3) V₂ = 0.901 0.0105 V₂ = = 0.0117 L 0.901 Final Answer: The bubble's final volume at the surface is 0.0117 L.
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