The centre of mass of the homogeneous body N = {(x, y, z) = ¸³ : √√x² + y² ≤ z ≤ 2 − x² − y² } - with mass m is (A) (B 1 11 0, 0, m 12 38 0, 0, 1 -% -% -%% m 1) 14/14 (1) m 1 D) 1/1 (a) П 0, 0, (D) 0, m 22 15 11 6 1- 끓이 15
The centre of mass of the homogeneous body N = {(x, y, z) = ¸³ : √√x² + y² ≤ z ≤ 2 − x² − y² } - with mass m is (A) (B 1 11 0, 0, m 12 38 0, 0, 1 -% -% -%% m 1) 14/14 (1) m 1 D) 1/1 (a) П 0, 0, (D) 0, m 22 15 11 6 1- 끓이 15
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter2: Functions And Graphs
Section2.6: Proportion And Variation
Problem 22E: Find the constant of proportionality. z is directly proportional to the sum of x and y. If x=2 and...
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the correct answer is A
please explain
Transcribed Image Text:The centre of mass of the homogeneous body
N = {(x, y, z) = ¸³ : √√x² + y² ≤ z ≤ 2 − x² − y² }
-
with mass m is
(A)
(B
1
11
0, 0,
m
12
38
0, 0,
1
-% -% -%%
m
1) 14/14 (1)
m
1
D) 1/1 (a)
П
0, 0,
(D) 0,
m
22
15
11
6
1-
끓이
15
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