Question 3: A sealed flask at room temperature contains a mixture of neon (Ne) and nitrogen (N2) gases. Ne has a mass of 3.25 g and exerts a pressure of 48.2 torr. . N2 contributes a pressure of 142 torr. • What is the mass of the N2 in the flask? • Atomic mass of Ne = 20.1797 g/mol • Atomic mass of N = 14.0067 g/mol Solution: We will use the Ideal Gas Law to determine the number of moles of each gas and calculate the mass of N2. PV = nRT where: • P = total pressure • V volume of the flask (same for both gases) n = number of moles of gas • R 0.0821 L atm/mol K • T = Room temperature (assume 298 K) Since both gases are in the same flask, their partial pressures correspond to their mole fractions. Step 1: Convert Pressures to Atmospheres 48.2 PNe = 0.0634 atm 760 142 PN2 = = 0.1868 atm 760 Step 2: Determine Moles of Ne nNe = mass molar mass 3.25 nNe 20.1797 nne 0.1611 mol Step 3: Use Partial Pressure Ratio to Find n Step 2: Determine Moles of Ne mass nNe molar mass 3.25 nNe = 20.1797 nNe =0.1611 mol Step 3: Use Partial Pressure Ratio to Find n N₂ Since pressure and moles are directly proportional, nNe PNe nN2 PN2 0.1611 0.0634 nN2 0.1868 0.1611 x 0.1868 NN2 = 0.0634 NN2 = 0.474 mol Step 4: Calculate Mass of N₂ Molar mass of N₂ = 2 × 14.0067 = 28.0134 g/mol. Mass of N2nN2 × MN2 Mass of N2 = (0.474)(28.0134) Mass of N2 = 13.28 g Final Answer: The mass of №2 in the flask is 13.28 g.
Question 3: A sealed flask at room temperature contains a mixture of neon (Ne) and nitrogen (N2) gases. Ne has a mass of 3.25 g and exerts a pressure of 48.2 torr. . N2 contributes a pressure of 142 torr. • What is the mass of the N2 in the flask? • Atomic mass of Ne = 20.1797 g/mol • Atomic mass of N = 14.0067 g/mol Solution: We will use the Ideal Gas Law to determine the number of moles of each gas and calculate the mass of N2. PV = nRT where: • P = total pressure • V volume of the flask (same for both gases) n = number of moles of gas • R 0.0821 L atm/mol K • T = Room temperature (assume 298 K) Since both gases are in the same flask, their partial pressures correspond to their mole fractions. Step 1: Convert Pressures to Atmospheres 48.2 PNe = 0.0634 atm 760 142 PN2 = = 0.1868 atm 760 Step 2: Determine Moles of Ne nNe = mass molar mass 3.25 nNe 20.1797 nne 0.1611 mol Step 3: Use Partial Pressure Ratio to Find n Step 2: Determine Moles of Ne mass nNe molar mass 3.25 nNe = 20.1797 nNe =0.1611 mol Step 3: Use Partial Pressure Ratio to Find n N₂ Since pressure and moles are directly proportional, nNe PNe nN2 PN2 0.1611 0.0634 nN2 0.1868 0.1611 x 0.1868 NN2 = 0.0634 NN2 = 0.474 mol Step 4: Calculate Mass of N₂ Molar mass of N₂ = 2 × 14.0067 = 28.0134 g/mol. Mass of N2nN2 × MN2 Mass of N2 = (0.474)(28.0134) Mass of N2 = 13.28 g Final Answer: The mass of №2 in the flask is 13.28 g.
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter12: Quadratic Functions
Section12.6: Solving Problems Involving Quadratic Equations
Problem 1.3E
Related questions
Question
100%
Both in images okk. Instructions.
"I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."
Transcribed Image Text:Question 3:
A sealed flask at room temperature contains a mixture of neon (Ne) and nitrogen (N2)
gases.
Ne has a mass of 3.25 g and exerts a pressure of 48.2 torr.
.
N2 contributes a pressure of 142 torr.
• What is the mass of the N2 in the flask?
• Atomic mass of Ne = 20.1797 g/mol
• Atomic mass of N = 14.0067 g/mol
Solution:
We will use the Ideal Gas Law to determine the number of moles of each gas and
calculate the mass of N2.
PV = nRT
where:
• P = total pressure
•
V volume of the flask (same for both gases)
n = number of moles of gas
•
R 0.0821 L atm/mol K
• T = Room temperature (assume 298 K)
Since both gases are in the same flask, their partial pressures correspond to their mole
fractions.
Step 1: Convert Pressures to Atmospheres
48.2
PNe
= 0.0634 atm
760
142
PN2
=
= 0.1868 atm
760
Step 2: Determine Moles of Ne
nNe =
mass
molar mass
3.25
nNe
20.1797
nne 0.1611 mol
Step 3: Use Partial Pressure Ratio to Find n
Transcribed Image Text:Step 2: Determine Moles of Ne
mass
nNe
molar mass
3.25
nNe =
20.1797
nNe =0.1611 mol
Step 3: Use Partial Pressure Ratio to Find n N₂
Since pressure and moles are directly proportional,
nNe
PNe
nN2
PN2
0.1611
0.0634
nN2
0.1868
0.1611 x 0.1868
NN2
=
0.0634
NN2
= 0.474 mol
Step 4: Calculate Mass of N₂
Molar mass of N₂ = 2 × 14.0067 = 28.0134 g/mol.
Mass of N2nN2 × MN2
Mass of N2
=
(0.474)(28.0134)
Mass of N2 = 13.28 g
Final Answer:
The mass of №2 in the flask is 13.28 g.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 3 images
Recommended textbooks for you
Algebra: Structure And Method, Book 1
Algebra
ISBN:
9780395977224
Author:
Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:
McDougal Littell
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Algebra: Structure And Method, Book 1
Algebra
ISBN:
9780395977224
Author:
Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:
McDougal Littell
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
