10 Given the Jordan curve y that is the counterclockwise oriented boundary of the set T = {z = x + iy : x, y Є R : x ≤ |y|, |z| ≤ 3}, the complex line integral z2 2(z − 1) (z² + 2iz – 1)` dz equals (A) 1- (B) 2π (i + 1) 2 (C) π (i − 1 ½) - П (D) (i − 2) 17/7

10 Given the Jordan curve y that is the counterclockwise oriented boundary of the set T = {z = x + iy : x, y Є R : x ≤ |y|, |z| ≤ 3}, the complex line integral z2 2(z − 1) (z² + 2iz – 1)` dz equals (A) 1- (B) 2π (i + 1) 2 (C) π (i − 1 ½) - П (D) (i − 2) 17/7

Elements Of Modern Algebra

8th Edition

ISBN:9781285463230

Author:Gilbert, Linda, Jimmie

Publisher:Gilbert, Linda, Jimmie

Chapter5: Rings, Integral Domains, And Fields

Section5.4: Ordered Integral Domains

Problem 8E: If x and y are elements of an ordered integral domain D, prove the following inequalities. a....

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Question

the correct answer is C
could you please show me how to do it using the residue theorem

10 Given the Jordan curve y that is the counterclockwise oriented boundary of the set
T = {z = x + iy : x, y Є R : x ≤ |y|, |z| ≤ 3}, the complex line integral
z2
2(z − 1) (z² + 2iz – 1)`
dz
equals
(A)
1-
(B) 2π
(i + 1)
2
(C) π (i − 1 ½)
-
П
(D) (i − 2) 17/7

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