equals: (A) 0 (B) 2πi/9 (C) -2π/3-2πi/9 (D) 1/9 9 The outward flux of the vector field F(x, y, z) = (1/2 + e +e+z (A) 2π the boundary of the region E = {(x, y, z) = R³: x² + y²+z2 <4, y ≥0, z> 0} is 22 , ex+z +e+y 2 through (B) T (C) -π (D) 2√2 10 Consider the vector field F(x, y, z) = (±±±², 5, +2²) Then N = defined on the set = {(x, y, z) = R³:-5
equals: (A) 0 (B) 2πi/9 (C) -2π/3-2πi/9 (D) 1/9 9 The outward flux of the vector field F(x, y, z) = (1/2 + e +e+z (A) 2π the boundary of the region E = {(x, y, z) = R³: x² + y²+z2 <4, y ≥0, z> 0} is 22 , ex+z +e+y 2 through (B) T (C) -π (D) 2√2 10 Consider the vector field F(x, y, z) = (±±±², 5, +2²) Then N = defined on the set = {(x, y, z) = R³:-5
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
For number 9
The answer is A
Could you show me how

Transcribed Image Text:equals:
(A) 0
(B) 2πi/9
(C) -2π/3-2πi/9
(D) 1/9
9 The outward flux of the vector field F(x, y, z) = (1/2 + e
+e+z
(A) 2π
the boundary of the region E = {(x, y, z) = R³: x² + y²+z2 <4, y ≥0, z> 0} is
22
, ex+z
+e+y
2
through
(B) T
(C) -π
(D) 2√2
10 Consider the vector field F(x, y, z) = (±±±², 5, +2²)
Then
N =
defined on the set
= {(x, y, z) = R³:-5<x<0,0< y < 6,0<z<1+x² + y²}.
(A) curl F(0, 0, 0) in
CL
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