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Use integration by parts to determine which of the reduction formulas is correct. O 6 sec (x) dx = 6 tan(x) sech - 1(x) +6 n-1 6 sec (x) dx = 6 tan(x) sec" - 1 (x) n-1 6 sec" (x) dx = 6 tan(x) sech - 2 (x) n-1 6 sec (x) dx = 6 tan(x) sec" - 2(x) n-1 n- 2 - secn - n-1 -2(x) dx, (n = 1) n-2 - 6 n - 1 / sech ·2(x) dx, (n + 1) n-2 6 sec -2(x) dx, (n + 1) n-1 2 - +6 n - sec - 2(x) dx, (n = 1) n-1

Use integration by parts to determine which of the reduction formulas is correct. O 6 sec (x) dx = 6 tan(x) sech - 1(x) +6 n-1 6 sec (x) dx = 6 tan(x) sec" - 1 (x) n-1 6 sec" (x) dx = 6 tan(x) sech - 2 (x) n-1 6 sec (x) dx = 6 tan(x) sec" - 2(x) n-1 n- 2 - secn - n-1 -2(x) dx, (n = 1) n-2 - 6 n - 1 / sech ·2(x) dx, (n + 1) n-2 6 sec -2(x) dx, (n + 1) n-1 2 - +6 n - sec - 2(x) dx, (n = 1) n-1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use integration by parts to determine which of the reduction formulas is correct. O 6 sec (x) dx = 6 tan(x) sech - 1(x) +6 n-1 6 sec (x) dx = 6 tan(x) sec" - 1 (x) n-1 6 sec" (x) dx = 6 tan(x) sech - 2 (x) n-1 6 sec (x) dx = 6 tan(x) sec" - 2(x) n-1 n- 2 - secn - n-1 -2(x) dx, (n = 1) n-2 - 6 n - 1 / sech ·2(x) dx, (n + 1) n-2 6 sec -2(x) dx, (n + 1) n-1 2 - +6 n - sec - 2(x) dx, (n = 1) n-1
Transcribed Image Text:Use integration by parts to determine which of the reduction formulas is correct. O 6 sec (x) dx = 6 tan(x) sech - 1(x) +6 n-1 6 sec (x) dx = 6 tan(x) sec" - 1 (x) n-1 6 sec" (x) dx = 6 tan(x) sech - 2 (x) n-1 6 sec (x) dx = 6 tan(x) sec" - 2(x) n-1 n- 2 - secn - n-1 -2(x) dx, (n = 1) n-2 - 6 n - 1 / sech ·2(x) dx, (n + 1) n-2 6 sec -2(x) dx, (n + 1) n-1 2 - +6 n - sec - 2(x) dx, (n = 1) n-1
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