Chapter 11.3, Problem 31LC

(a)

Interpretation Introduction

Interpretation: To determine the net ionic balanced chemical reaction.

Concept Introduction: The type of chemical reaction in which the count of reactant will be identical to a count of product is referred to as a balanced chemical reaction.

Answer to Problem 31LC

The balanced net ionic chemical reaction is ${\text{Pb}}^{\text{2+}}\left(\text{aq}\right){\text{+SO}}^{\text{-}}{}_{\text{4}}\left(\text{aq}\right)\to {\text{PbSO}}_{\text{4}}\left(\text{aq}\right)$

Explanation of Solution

The given chemical reaction is:

  ${\text{Pb(NO}}_{\text{3}}{\text{)}}_{\text{2}}\left(\text{aq}\right){\text{+H}}_{\text{2}}{\text{SO}}_{\text{4}}\left(\text{aq}\right)\to {\text{PbSO}}_{\text{4}}\left(\text{s}\right){\text{+HNO}}_{\text{3}}\left(\text{aq}\right)$

The ionic equation for this reaction can be written as:

  ${\text{Pb}}^{2+}\text{(aq)}{\text{+ 2NO}}_{\text{3}}{}^{-}\left(\text{aq}\right){\text{+2H}}^{+}\left(\text{aq}\right){\text{+SO}}_{\text{4}}{}^{-}\left(\text{aq}\right)\to {\text{PbSO}}_{\text{4}}\left(\text{s}\right){\text{+2H}}^{+}\text{(aq)}{\text{+2NO}}_{\text{3}}{}^{\_}\left(\text{aq}\right)$

By canceling the hydrogen ion and the nitrate ion, the net ionic equation will be:

  ${\text{Pb}}^{\text{2+}}\left(\text{aq}\right){\text{+SO}}^{\text{-}}{}_{\text{4}}\left(\text{aq}\right)\to {\text{PbSO}}_{\text{4}}\left(\text{aq}\right)$

(b)

Interpretation Introduction

Interpretation: To determine the net ionic balanced chemical reaction.

Concept Introduction: The type of chemical reaction in which the count of reactant will be identical to a count of product is referred to as a balanced chemical reaction.

Answer to Problem 31LC

The balanced net chemical reaction is ${\text{Pb}}^{\text{2+}}\left(\text{aq}\right){\text{+2Cl}}^{-}\left(\text{aq}\right)\to {\text{PbCl}}_2\left(\text{aq}\right)$

Explanation of Solution

The given chemical reaction is:

  ${\text{Pb(CH}}_{\text{3}}{\text{COO)}}_{\text{2}}\left(\text{aq}\right)\text{+2HCl}\left(\text{aq}\right)\to {\text{PbCl}}_{\text{2}}\left(\text{s}\right){\text{+2CH}}_{\text{3}}\text{COOH}\left(\text{aq}\right)$

The ionic equation for this reaction can be written as:

  ${\text{2Pb}}^{\text{2+}}\text{(aq)}{\text{+ 2CH}}_{\text{3}}{\text{COO}}^{\text{-}}\left(\text{aq}\right){\text{+2H}}^{\text{+}}\left(\text{aq}\right){\text{+2Cl}}^{\text{-}}\left(\text{aq}\right)\to {\text{PbCl}}_{\text{2}}\left(\text{s}\right){\text{+2H}}^{\text{+}}\text{(aq)}{\text{+2CH}}_{\text{3}}{\text{COO}}^{\text{-}}\left(\text{aq}\right)$

By canceling the acetate ion and the hydrogen ion, the net ionic equation will be:

  ${\text{Pb}}^{\text{2+}}\left(\text{aq}\right){\text{+2Cl}}^{-}\left(\text{aq}\right)\to {\text{PbCl}}_2\left(\text{aq}\right)$

(c)

Interpretation Introduction

Interpretation: To determine the net ionic balanced chemical reaction.

Concept Introduction: The type of chemical reaction in which the count of reactant will be identical to a count of product is referred to as a balanced chemical reaction.

Answer to Problem 31LC

The balanced net chemical reaction is ${\text{Fe}}^{\text{3+}}\left(\text{aq}\right){\text{+PO}}_{\text{4}}{}^{\text{-}}\left(\text{aq}\right)\to {\text{FePO}}_{\text{4}}\left(s\right)$

Explanation of Solution

The given chemical reaction is:

  ${\text{Na}}_{\text{3}}{\text{PO}}_{\text{4}}\left(\text{aq}\right){\text{+FeCl}}_{\text{3}}\left(\text{aq}\right)\to \text{NaCl}\left(\text{aq}\right){\text{+FePO}}_{\text{4}}\left(\text{s}\right)$

The ionic equation for this reaction can be written as:

  ${\text{3Na}}^{\text{+}}\left(\text{aq}\right){\text{+PO}}_{\text{4}}{}^{\text{-}}\left(\text{aq}\right){\text{+Fe}}^{\text{3+}}\left(\text{aq}\right)\text{+}{\text{3Cl}}^{\text{-}}\left(\text{aq}\right)\to {\text{Na}}^{\text{+}}\left(\text{aq}\right)\text{+}{\text{Cl}}^{\text{-}}\left(\text{aq}\right){\text{+FePO}}_{\text{4}}\left(\text{s}\right)$

By canceling the sodium ion and the chloride ion, the net ionic equation will be:

  ${\text{Fe}}^{\text{3+}}\left(\text{aq}\right){\text{+PO}}_{\text{4}}{}^{\text{-}}\left(\text{aq}\right)\to {\text{FePO}}_{\text{4}}\left(s\right)$

(d)

Interpretation Introduction

Interpretation: To determine the net balanced chemical reaction.

Concept Introduction: The type of chemical reaction in which the count of reactant will be identical to a count of product is referred to as a balanced chemical reaction.

Answer to Problem 31LC

The balanced net chemical reaction is

  ${\text{Pb}}^{\text{2+}}\left(\text{aq}\right){\text{+2Cl}}^{-}\left(\text{aq}\right)\to {\text{PbCl}}_2\left(\text{aq}\right)$

Explanation of Solution

The given chemical reaction is:

  ${{\text{(NH}}_{\text{4}}\text{)}}_{\text{2}}\text{S}\left(\text{aq}\right){\text{+Co(NO}}_{\text{3}}{\text{)}}_{\text{2}}\left(\text{aq}\right)\to \text{CoS}\left(\text{s}\right){\text{+2NH}}_{\text{4}}{\text{NO}}_{\text{3}}\left(\text{aq}\right)$

The ionic equation for this reaction can be written as:

  ${\text{2(NH}}_{\text{4}}{\text{)}}^{+}\left(\text{aq}\right)+{\text{S}}^{2-}\left(\text{aq}\right){\text{+Co}}^{2+}\left(\text{aq}\right)+{{\text{(NO}}_{\text{3}}\text{)}}^{\_}\left(\text{aq}\right)\to \text{CoS}\left(\text{s}\right){\text{+2NH}}_{\text{4}}{}^{+}\left(\text{aq}\right){\text{+NO}}_{\text{3}}{}^{-}\left(\text{aq}\right)$

By canceling the ammonium ion and the nitrate ion, the net ionic equation will be:

  ${\text{Co}}^{\text{2+}}\left(\text{aq}\right){\text{+S}}^{\text{2-}}\left(\text{aq}\right)\to \text{CoS}\left(s\right)$