Chapter 11.1, Problem 10LC

(a)

Interpretation Introduction

Interpretation: The given reactions are to be balanced.

Concept Introduction : According to the law of conservation of mass, the mass can neither be created nor be destroyed. Every reaction must be balanced.

Answer to Problem 10LC

The balanced equation is ${\text{2SO}}_{\text{2}}\left(g\right)+{\text{O}}_{\text{2}}\left(g\right)\to 2{\text{SO}}_{\text{3}}\left(g\right)$

Explanation of Solution

The unbalanced equation is given as:

  ${\text{SO}}_{\text{2}}\left(g\right)+{\text{O}}_{\text{2}}\left(g\right)\to {\text{SO}}_{\text{3}}\left(g\right)$

The coefficient of 2 is placed before ${\text{SO}}_{\text{2}}$ and ${\text{SO}}_{\text{3}}$ . The balanced equation is:

  ${\text{2SO}}_{\text{2}}\left(g\right)+{\text{O}}_{\text{2}}\left(g\right)\to 2{\text{SO}}_{\text{3}}\left(g\right)$

(b)

Interpretation Introduction

Interpretation: The given reactions are to be balanced.

Concept Introduction : According to the law of conservation of mass, the mass can neither be created nor be destroyed. Every reaction must be balanced.

Answer to Problem 10LC

The balanced equation is ${\text{Fe}}_2{\text{O}}_3\left(s\right)+3{\text{H}}_{\text{2}}\left(g\right)\to 2\text{Fe}\left(s\right)+3{\text{H}}_{\text{2}}\text{O}\left(l\right)$

Explanation of Solution

The unbalanced equation is given as:

  ${\text{Fe}}_2{\text{O}}_3\left(s\right)+{\text{H}}_{\text{2}}\left(g\right)\to \text{Fe}\left(s\right)+{\text{H}}_{\text{2}}\text{O}\left(l\right)$

The coefficient of 2 is placed before $\text{Fe}$ , 3 is placed before ${\text{H}}_{\text{2}}$ and ${\text{H}}_{\text{2}}\text{O}$ . The balanced equation is:

  ${\text{Fe}}_2{\text{O}}_3\left(s\right)+3{\text{H}}_{\text{2}}\left(g\right)\to 2\text{Fe}\left(s\right)+3{\text{H}}_{\text{2}}\text{O}\left(l\right)$

(c)

Interpretation Introduction

Interpretation: The given reactions are to be balanced.

Concept Introduction : According to the law of conservation of mass, the mass can neither be created nor be destroyed. Every reaction must be balanced.

Answer to Problem 10LC

The balanced equation is $\text{4P}\left(s\right)+5{\text{O}}_{\text{2}}\left(g\right)\to {\text{P}}_4{\text{O}}_{\text{10}}\left(s\right)$

Explanation of Solution

The unbalanced equation is given as:

  $\text{P}\left(s\right)+{\text{O}}_{\text{2}}\left(g\right)\to {\text{P}}_4{\text{O}}_{\text{10}}\left(s\right)$

The coefficient of 4 is placed before $\text{P}$ and 5 is placed before ${\text{O}}_{\text{2}}$ . The balanced equation is:

  $\text{4P}\left(s\right)+5{\text{O}}_{\text{2}}\left(g\right)\to {\text{P}}_4{\text{O}}_{\text{10}}\left(s\right)$

(d)

Interpretation Introduction

Interpretation: The given reactions are to be balanced.

Concept Introduction : According to the law of conservation of mass, the mass can neither be created nor be destroyed. Every reaction must be balanced.

Answer to Problem 10LC

The balanced equation is $\text{2Al}\left(s\right)+{\text{N}}_{\text{2}}\left(g\right)\to 2\text{AlN}\left(s\right)$

Explanation of Solution

The unbalanced equation is given as:

  $\text{Al}\left(s\right)+{\text{N}}_{\text{2}}\left(g\right)\to \text{AlN}\left(s\right)$

The coefficient of 2 is placed before $\text{Al}$ and $\text{AlN}$ . The balanced equation is:

  $\text{2Al}\left(s\right)+{\text{N}}_{\text{2}}\left(g\right)\to 2\text{AlN}\left(s\right)$