Chapter 11.3, Problem 32LC

(a)

Interpretation Introduction

Interpretation: To determine the precipitate in the given chemical reaction.

Concept Introduction: When more than one atom or molecule will get reacted with each other, they will form a different kind of atom or molecule. This process is named a chemical reaction.

Answer to Problem 32LC

The precipitate will be ${\text{BaSO}}_{\text{4}}$

Explanation of Solution

When barium chloride ( ${\text{BaCl}}_{\text{2}}$ ) and sulfuric acid ( ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ ) are reacted, barium ions ( ${\text{Ba}}^{\text{2+}}$ ) and sulfate ions ( ${\text{SO}}_{\text{4}}^{\text{2-}}$ ) immediately mix with other to form a white precipitate of ${\text{BaSO}}_{\text{4}}$ and the other product is hydrochloric acid (HCl).

The Balanced Chemical equation is:

  ${\text{BaCl}}_{\text{2}}{\text{+H}}_{\text{2}}{\text{SO}}_{\text{4}}\to {\text{BaSO}}_{\text{4}}\text{+2HCl}$ .

(b)

Interpretation Introduction

Interpretation: To determine the precipitate in the given chemical reaction.

Concept Introduction: When more than one atom or molecule will get reacted with each other then they will form a different kind of atom or molecule. This process is named a chemical reaction.

Answer to Problem 32LC

The precipitate will be $\text{[}{\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{SO}}_{\text{4}}\text{]}$

Explanation of Solution

When Aluminium sulfate and Ammonium hydroxide are reacted, Ammonium ions ${\text{(NH}}_{\text{4}}{}^{\text{+}}\text{)}$ (NH₄⁺) and sulfate ions $\left({\text{SO}}_{\text{4}}{}^{\text{2-}}\right)$ immediately mix with other and forms precipitate of Ammonium sulfate $\text{[}{\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{SO}}_{\text{4}}\text{]}$ and the other product is Aluminium hydroxide $\text{[Al}{\left(\text{OH}\right)}_{\text{3}}\text{]}$

The Balanced Chemical Equation is:

  ${\text{Al}}_{\text{2}}{\left({\text{SO}}_{\text{4}}\right)}_{\text{3}}{\text{ + 6NH}}_{\text{4}}\text{OH }\to \text{2Al}{\left(\text{OH}\right)}_{\text{3}}\text{ + 3}{\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{SO}}_{\text{4}}$

(d)

Interpretation Introduction

Interpretation: To determine the precipitate in the given chemical reaction.

Concept Introduction: When more than one atom or molecule will get combined, they will form a different kind of atom or molecule. This process is named a chemical reaction.

Answer to Problem 32LC

The precipitate will be ${\text{(PbCl}}_{\text{2}}\text{)}$

Explanation of Solution

When we react with calcium chloride ( ${\text{CaCl}}_{\text{2}}$ ) and lead nitrate $\text{[Pb}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\text{]}$ , then precipitate of lead chloride ${\text{(PbCl}}_{\text{2}}\text{)}$ and calcium nitrate $\text{[Ca}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\text{]}$ are formed.

The Balanced Chemical Equation is:

  ${\text{CaCl}}_{\text{2}}\text{ + Pb}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\to \text{ Ca}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}{\text{ + PbCl}}_{\text{2}}$

(e)

Interpretation Introduction

Interpretation: To determine the precipitate in the given chemical reaction.

Concept Introduction: When more than one atom or molecule will get combined, they will form a different kind of atom or molecule. This process is named a chemical reaction.

Answer to Problem 32LC

The precipitate will be ${\text{(CaCO}}_{\text{3}}\text{)}$

Explanation of Solution

When we react with calcium nitrate $\text{[Ca}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\text{]}$ and sodium carbonate ${\text{[Na}}_{\text{2}}{\text{CO}}_{\text{3}}\text{]}$ , then precipitate of calcium carbonate ${\text{(CaCO}}_{\text{3}}\text{)}$ and sodium nitrate ${\text{[NaNO}}_{\text{3}}\text{]}$ are formed.

The Balanced Chemical Equation is:

  $\text{Ca}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}{\text{ + Na}}_{\text{2}}{\text{CO}}_{\text{3}}\to {\text{CaCO}}_{\text{3}}{\text{ + 2NaNO}}_{\text{3}}$