Chapter 11, Problem 47A

(a)

Interpretation Introduction

Interpretation:

To complete and write the net ionic equation.

Concept Introduction:

An ionic equation is a chemical equation in which ions are represented in the aqueous solution. If all the ions are represented, it is known as a complete ionic equation but when spectator ions are removed then, it is known as the net ionic equation.

Answer to Problem 47A

The balanced net ionic equation is: $\text{2Al(}s{\text{) + 6H}}^{+}(aq)\to {\text{ 2Al}}^{3+}{\text{(aq)+ 3H}}_2(g)$

Explanation of Solution

To balance the ionic equation, some steps need to be followed and those are:

Step $1$ : Write the reactants.

Step $2$ : Identify the possible pairing of anions and cations to give insoluble products.

Step $3$: Remove the spectator ions.

The ionic equation given is:

  $\text{Al}\left(s\right)+{\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}\left(aq\right)$

Step $1$ : $\text{Al(}s{\text{) + 2H}}^{+}(aq)+{\text{SO}}^{2-}{}_4(aq)\to$

Step $2$ :

  $\text{2Al(}s{\text{) + 6H}}^{+}(aq)+3{\text{SO}}^{2-}{}_4(aq)\to {\text{ 2Al}}^{3+}{\text{(aq) + 3SO}}_4{{}^2}^{-}\text{(}aq{\text{)+ 3H}}_2(g)$

Step 3: $\text{2Al(}s{\text{) + 6H}}^{+}(aq)\to {\text{ 2Al}}^{3+}{\text{(aq)+ 3H}}_2(g)$

(b)

Interpretation Introduction

Interpretation:

To complete and write the net ionic equation.

Concept Introduction:

An ionic equation is a chemical equation in which ions are represented in an aqueous solution. If all the ions are represented then, it is known as a complete ionic equation but when spectator ions are removed then, it is known as the net ionic equation.

Answer to Problem 47A

The balanced net ionic equation is: ${\text{H}}^{+}\text{(aq)+ }O{H}^{-}(aq)\to {\text{H}}_{2}O(aq)$ .

Explanation of Solution

To balance the ionic equation, some steps need to be followed and those are:

Step $1$ : Write the reactants.

Step $2$ : Identify the possible pairing of anions and cations to give insoluble products.

Step $3$: Remove the spectator ions.

The ionic equation given is:

  $\text{2HCl}(aq)+\text{Ba(}OH{)}_2(aq)\to$

Step $1$ : ${\text{2H}}^{+}{\text{(aq) + 2Cl}}^{-}(aq)+{\text{Ba}}^{2+}(aq)+2O{H}^{-}(aq)\to$

Step $2$ :

  ${\text{2H}}^{+}{\text{(aq) + 2Cl}}^{-}(aq)+{\text{Ba}}^{2+}(aq)+2O{H}^{-}(aq)\to {\text{ Ba}}^{2+}{\text{(aq) + 2Cl}}^{-}\text{(}aq{\text{)+ 2H}}^{+}(aq)+2O{H}^{-}(aq)$

Step $3$ : ${\text{H}}^{+}\text{(aq)+ }O{H}^{-}(aq)\to {\text{H}}_{2}O(aq)$

(c)

Interpretation Introduction

Interpretation:

To complete and write the net ionic equation.

Concept Introduction:

An ionic equation is a chemical equation in which ions are represented in an aqueous solution. If all the ions are represented then, it is known as a complete ionic equation but when spectator ions are removed then, it is known as the net ionic equation.

Answer to Problem 47A

There is no reaction between gold and Hydrochloric acid.

Explanation of Solution

To balance the ionic equation, some steps need to be followed and those are:

Step $1$ : Write the reactants.

Step $2$ : Identify the possible pairing of anions and cations to give insoluble products.

Step $3$: Remove the spectator ions.

There is no reaction between gold and hydrochloric acid as gold is a noble element and it is not reactive.