Chapter 11, Problem 22P

Interpretation Introduction

(a)

Interpretation:

The compound $\text{LiBr}$ needs to be classified as organic or inorganic compound.

Concept Introduction:

Organic compound is that compound in which carbon is covalently bonded to hydrogen atom or to oxygen or nitrogen atom. For example: ${\text{CH}}_{\text{4}}$ , ${\text{C}}_2{\text{H}}_6$ etc.

Inorganic compound is the one in which no carbon hydrogen $\left(\text{C}-\text{H}\right)$ bond present. For example: ${\text{NO}}_{\text{2}}$ , $\text{NaCl}$ etc.

Interpretation Introduction

(b)

Interpretation:

The compound $\text{HCl}$ needs to be classified as organic or inorganic compound.

Concept Introduction:

Organic compound is that compound in which carbon is covalently bonded to hydrogen atom or to oxygen or nitrogen atom. For example: ${\text{CH}}_{\text{4}}$ , ${\text{C}}_2{\text{H}}_6$ etc.

Inorganic compound is the one in which no carbon hydrogen $\left(\text{C}-\text{H}\right)$ bond present. For example: ${\text{NO}}_{\text{2}}$ , $\text{NaCl}$ etc.

Interpretation Introduction

(c)

Interpretation:

The compound ${\text{CH}}_{\text{5}}\text{N}$ needs to be classified as organic or inorganic compound.

Concept Introduction:

Organic compound is that compound in which carbon is covalently bonded to hydrogen atom or to oxygen or nitrogen atom. For example: ${\text{CH}}_{\text{4}}$ , ${\text{C}}_2{\text{H}}_6$ etc.

Inorganic compound is the one in which no carbon hydrogen $\left(\text{C}-\text{H}\right)$ bond present. For example: ${\text{NO}}_{\text{2}}$ , $\text{NaCl}$ etc.