Chapter 11, Problem 21P

Interpretation Introduction

(a)

Interpretation:

The compound ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ needs to be classified as organic or inorganic compound.

Concept Introduction:

Organic compound is that compound in which carbon is covalently bonded to hydrogen atom or to oxygen or nitrogen atom. For example: ${\text{CH}}_{\text{4}}$ , ${\text{C}}_2{\text{H}}_6$ etc.

Inorganic compound is the one in which no carbon hydrogen $\left(\text{C}-\text{H}\right)$ bond present. For example: ${\text{NO}}_{\text{2}}$ , $\text{NaCl}$ etc.

Answer to Problem 21P

  ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ is an inorganic compound.

Explanation of Solution

The structure of ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ is as follows:

  

In the structure of ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ , no $\left(\text{C}-\text{H}\right)$ bond is present. So, the compound is inorganic compound.

Interpretation Introduction

(b)

Interpretation:

The compound ${\text{Br}}_{\text{2}}$ needs to be classified as organic or inorganic compound.

Concept Introduction:

Organic compound is that compound in which carbon is covalently bonded to hydrogen atom or to oxygen or nitrogen atom. For example: ${\text{CH}}_{\text{4}}$ , ${\text{C}}_2{\text{H}}_6$ etc.

Inorganic compound is the one in which no carbon hydrogen $\left(\text{C}-\text{H}\right)$ bond present. For example: ${\text{NO}}_{\text{2}}$ , $\text{NaCl}$ etc.

Answer to Problem 21P

  ${\text{Br}}_{\text{2}}$ is an inorganic compound.

Explanation of Solution

The structure of ${\text{Br}}_{\text{2}}$ is as follows:

  

In compound ${\text{Br}}_{\text{2}}$ , no carbon hydrogen $\left(\text{C}-\text{H}\right)$ bond present, so the compound does not follow the criteria of organic compound. So, the compound ${\text{Br}}_{\text{2}}$ is an inorganic compound.

Interpretation Introduction

(c)

Interpretation:

The compound ${\text{C}}_5{\text{H}}_{12}$ needs to be classified as organic or inorganic compound.

Concept Introduction:

Organic compound is that compound in which carbon is covalently bonded to hydrogen atom or to oxygen or nitrogen atom. For example: ${\text{CH}}_{\text{4}}$ , ${\text{C}}_2{\text{H}}_6$ etc.

Inorganic compound is the one in which no carbon hydrogen $\left(\text{C}-\text{H}\right)$ bond present. For example: ${\text{NO}}_{\text{2}}$ , $\text{NaCl}$ etc.

Answer to Problem 21P

  ${\text{C}}_5{\text{H}}_{12}$ is an organic compound.

Explanation of Solution

The structure of ${\text{C}}_5{\text{H}}_{12}$ is as follows:

  

In ${\text{C}}_5{\text{H}}_{12}$ , C-H bonds are present that means it satisfy the condition for an organic compound. So, the compound ${\text{C}}_5{\text{H}}_{12}$ is an organic compound.