The reason behind much higher yield of 2-bromohexane when the reaction mixture stirred compared to unstirred situation should be given. Concept introduction: Alkenes are considered electron rich and undergoes addition reaction in presence of electrophilic halo acids. 2-bromohexane is the product obtained when HBr adds to polar 1 − hexene by electrophilic addition reaction. The product formed is governed by Markovnikov’s Rule. Rule suggests that negative part of halo acid HX must go to the carbon that has more alkyl substituents or less H atoms. This is also justified as intermediate tertiary carbocation involved in this pathway is highly stable intermediate.

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Answer 1

Question

Chapter 10.5, Problem 4E

Interpretation Introduction

Interpretation:The reason behind much higher yield of 2-bromohexane when the reaction mixture stirred compared to unstirred situation should be given.

Concept introduction:Alkenes are considered electron rich and undergoes addition reaction in presence of electrophilic halo acids. 2-bromohexane is the product obtained when HBr adds to polar 1−hexene by electrophilic addition reaction.

The product formed is governed by Markovnikov’s Rule. Rule suggests that negative part of halo acid HX must go to the carbon that has more alkyl substituents or less H atoms. This is also justified as intermediate tertiary carbocation involved in this pathway is highly stable intermediate.

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Answer 2

Question

Chapter 10.5, Problem 4E

Interpretation Introduction

Interpretation:The reason behind much higher yield of 2-bromohexane when the reaction mixture stirred compared to unstirred situation should be given.

Concept introduction:Alkenes are considered electron rich and undergoes addition reaction in presence of electrophilic halo acids. 2-bromohexane is the product obtained when HBr adds to polar 1−hexene by electrophilic addition reaction.

The product formed is governed by Markovnikov’s Rule. Rule suggests that negative part of halo acid HX must go to the carbon that has more alkyl substituents or less H atoms. This is also justified as intermediate tertiary carbocation involved in this pathway is highly stable intermediate.

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Answer 3

Question

Chapter 10.5, Problem 4E

Interpretation Introduction

Interpretation:The reason behind much higher yield of 2-bromohexane when the reaction mixture stirred compared to unstirred situation should be given.

Concept introduction:Alkenes are considered electron rich and undergoes addition reaction in presence of electrophilic halo acids. 2-bromohexane is the product obtained when HBr adds to polar 1−hexene by electrophilic addition reaction.

The product formed is governed by Markovnikov’s Rule. Rule suggests that negative part of halo acid HX must go to the carbon that has more alkyl substituents or less H atoms. This is also justified as intermediate tertiary carbocation involved in this pathway is highly stable intermediate.

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Answer 4

Question

Chapter 10.5, Problem 4E

Interpretation Introduction

Interpretation:The reason behind much higher yield of 2-bromohexane when the reaction mixture stirred compared to unstirred situation should be given.

Concept introduction:Alkenes are considered electron rich and undergoes addition reaction in presence of electrophilic halo acids. 2-bromohexane is the product obtained when HBr adds to polar 1−hexene by electrophilic addition reaction.

The product formed is governed by Markovnikov’s Rule. Rule suggests that negative part of halo acid HX must go to the carbon that has more alkyl substituents or less H atoms. This is also justified as intermediate tertiary carbocation involved in this pathway is highly stable intermediate.

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Answer 5

Chapter 10.5, Problem 4E

Interpretation Introduction

Interpretation:The reason behind much higher yield of 2-bromohexane when the reaction mixture stirred compared to unstirred situation should be given.

Concept introduction:Alkenes are considered electron rich and undergoes addition reaction in presence of electrophilic halo acids. 2-bromohexane is the product obtained when HBr adds to polar 1−hexene by electrophilic addition reaction.

The product formed is governed by Markovnikov’s Rule. Rule suggests that negative part of halo acid HX must go to the carbon that has more alkyl substituents or less H atoms. This is also justified as intermediate tertiary carbocation involved in this pathway is highly stable intermediate.

Answer 6

Chapter 10.5, Problem 4E

Interpretation Introduction

Interpretation:The reason behind much higher yield of 2-bromohexane when the reaction mixture stirred compared to unstirred situation should be given.

Concept introduction:Alkenes are considered electron rich and undergoes addition reaction in presence of electrophilic halo acids. 2-bromohexane is the product obtained when HBr adds to polar 1−hexene by electrophilic addition reaction.

The product formed is governed by Markovnikov’s Rule. Rule suggests that negative part of halo acid HX must go to the carbon that has more alkyl substituents or less H atoms. This is also justified as intermediate tertiary carbocation involved in this pathway is highly stable intermediate.

Answer 7

Chapter 10.5, Problem 4E

Interpretation Introduction

Interpretation:The reason behind much higher yield of 2-bromohexane when the reaction mixture stirred compared to unstirred situation should be given.

Concept introduction:Alkenes are considered electron rich and undergoes addition reaction in presence of electrophilic halo acids. 2-bromohexane is the product obtained when HBr adds to polar 1−hexene by electrophilic addition reaction.

The product formed is governed by Markovnikov’s Rule. Rule suggests that negative part of halo acid HX must go to the carbon that has more alkyl substituents or less H atoms. This is also justified as intermediate tertiary carbocation involved in this pathway is highly stable intermediate.

Answer 8

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Answer 11

Ch. 10.2 - Prob. 1E Ch. 10.2 - Prob. 2E Ch. 10.2 - Prob. 3E Ch. 10.2 - Prob. 4E Ch. 10.2 - Prob. 5E Ch. 10.2 - Prob. 6E Ch. 10.2 - Prob. 7E Ch. 10.2 - Prob. 8E Ch. 10.2 - Prob. 9E Ch. 10.2 - Prob. 10E

Solution Summary: The author explains the reason behind higher yield of 2-bromohexane when the reaction mixture stirred compared to unstirred situation.

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