Interpretation:
To draw two different three-dimensional representations for CH2Cl2 (dichloromethane) using wedges and dashes
Concept introduction:
In the stereochemistry, various methods are depicted to represent three dimensional representations. Methane, a tetrahedral model, substituted by four different or same types of ligands at the vertices of the tetrahedron, which is not apparent in the
Wedge or solid heavy line represent a bond that project above the plane or pointing towards the observer. Broken wedge or dashed lines are that project below the plane or pointing away from the observer. The wedge and dashed lines for the sample methane is shown below in the Fig.1. Structure A and B represent a normal structure. Structure C represent the wedge and dashed lines. In the Structure C, a represent wedge, b represent dashed lines and c, d represent solid lines.
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- Each sketch below shows three objects with an electric charge. In each case, decide whether there is a net force acting on the object outlined in green. If there is a net force, decide whether it pushes the green-ring object to the left or right. Then select the appropriate button under the sketch. For example, if there is a net force pushing the green-ring object in the first sketch to the left, select the left button under the first sketch. If there is no net force on the green-ring object in the second sketch, select the middle button under the second sketch. And so on. Explanation -2 Check +2 X -2 ♫ ola Ar © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility A C allarrow_forwardEach sketch below shows three objects with an electric charge. In each case, decide whether there is a net force acting on the object outlined in green. If there is a net force, decide whether it pushes the green-ring object to the left or right. Then select the appropriate button under the sketch. For example, if there is a net force pushing the green-ring object in the first sketch to the left, select the left button under the first sketch. If there is no net force on the green-ring object in the second sketch, select the middle button under the second sketch. And so on. +1 Explanation Check 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use I Privacy Acce acer backspace deletearrow_forwardEach sketch below shows three objects with an electric charge. In each case, decide whether there is a net force acting on the object outlined in green. If there is a net force, decide whether it pushes the green-ring object to the left or right. Then select the appropriate button under the sketch. For example, if there is a net force pushing the green-ring object in the first sketch to the left, select the left button under the first sketch. If there is no net force on the green-ring object in the second sketch, select the middle button under the second sketch. And so on. ola -2 +3 -2 -2 I Don't Know Submit 2022 McGraw Hill LLC. AL Riahts Reserved. Terms of Use I Privacy Center Accessibility etv 16 Dl 18 80 & % 6 7 8O 4.arrow_forward
- Each sketch below shows three objects with an electric charge. In each case, decide whether there is a net force acting on the object outlined in green. If there is a net force, decide whether it pushes the green-ring object to the left or right. Then select the appropriate button under the sketch. For example, if there is a net force pushing the green-ring object in the first sketch to the left, select the left button under the first sketch. If there is no net force on the green-ring object in the second sketch, select the middle button under the second sketch. And so on. 42 +3 I Don't Know Submit O 2022 McGraw Hill LLC AM Rights Reserved Terms of Use DII DO 80 F10 F7 FB F5 F4 esc F2 F3 1 $ % & @ 23 delete %3D ! 7 4 1 Y Q W E tab wー * CO つarrow_forwardEach sketch below shows three objects with an electric charge. In each case, decide whether there is a net force acting on the object outlined in green. If there is a net force, decide whether it pushes the green-ring object to the left or right. Then select the appropriate button under the sketch. if there is a net force pushing the green-ring object in the first sketch to the left, select the left button under the first sketch. If there is no net force on the green-ring object in the second sketch, select the middle button under the second sketch. And so on.arrow_forwardA chemist, during the course of an analysis, runs across a chemical composed of carbon, hydrogen, and oxygen in the proportion 1:2:1 and having a six-sided molecular shape. It is probably (a) a pentose, (b) an amino acid, (c) a fatty acid, (d) a monosaccharide, (e) a nucleic acid.arrow_forward
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- The structures of 2,2-dimethylpropane and pentane are shown. H H H H CH3 H3C CH3 CH3 surface area of 2,2-dimethylpropane surface area of pentane = pentane H = O 2,2-dimethylpropane H 2,2-dimethylpropane Calculate the surface area of each compound, assuming that 2,2-dimethylpropane is approximately spherical with a radius of 254 pm and that pentane is approximately a rectangular prism with dimensions of 295 pm × 692 pm × 766 pm. H H H Select the molecule that has the larger surface area. pentane H H Select the true statement about the boiling points of these two molecules. Pentane has the higher boiling point because it has the smaller surface area. 2,2-Dimethylproane has the higher boiling point because it has the larger surface area. Pentane has the higher boiling point because it has the larger surface area. O 2,2-Dimethylproane has the higher boiling point because it has the smaller surface area. 2 pm² 2 pm²arrow_forwardCan you answer the following questionsarrow_forwardcondensed state molecules held together in a rigid configuration are called a) polymers b) gases c) solids d) liquidsarrow_forward