Organic Chemistry-Package(Custom)
Organic Chemistry-Package(Custom)
4th Edition
ISBN: 9781259141089
Author: SMITH
Publisher: MCG
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Chapter 1, Problem 1.43P

Draw one valid Lewis structure for each compound. Assume the atoms are arranged as drawn.Chapter 1, Problem 1.43P, Draw one valid Lewis structure for each compound. Assume the atoms are arranged as drawn.

Expert Solution
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Interpretation Introduction

(a)

Interpretation: A valid Lewis structure for the given compound is to be drawn.

Concept introduction: The arrangement of valence electrons among the atoms present in a molecule is represented by the Lewis structure of that molecule. The electron pairs in the molecule are considered to be delocalized.

Answer to Problem 1.43P

The valid Lewis structure for the given compound is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  1

Explanation of Solution

The given compound is CH2N2. The atoms are arranged as,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  2

Figure 1

The valence electrons are counted as,

(1C×4e)+(2H×1e)+(2N×5e)=4e+2e+10e=16e

The bonds and lone pairs are added in the given arrangement of atoms. The valid Lewis structure is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  3

Figure 2

Conclusion

The valid Lewis structure for the given compound is shown in Figure 2.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation: A valid Lewis structure for the given compound is to be drawn.

Concept introduction: The arrangement of valence electrons among the atoms present in a molecule is represented by the Lewis structure of that molecule. The electron pairs in the molecule are considered to be delocalized.

Answer to Problem 1.43P

The valid Lewis structure for the given compound is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  4

Explanation of Solution

The given compound is CH3CNO. The atoms are arranged as,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  5

Figure 3

The valence electrons are counted as,

(2C×4e)+(3H×1e)+(1N×5e)+(1O×6e)=8e+3e+5e+6e=22e

The bonds and lone pairs are added in the given arrangement of atoms. The valid Lewis structure is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  6

Figure 4

Conclusion

The valid Lewis structure for the given compound is shown in Figure 4.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation: A valid Lewis structure for the given compound is to be drawn.

Concept introduction: The arrangement of valence electrons among the atoms present in a molecule is represented by the Lewis structure of that molecule. The electron pairs in the molecule are considered to be delocalized.

Answer to Problem 1.43P

The valid Lewis structure for the given compound is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  7

Explanation of Solution

The given compound is CH3NO2. The atoms are arranged as,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  8

Figure 5

The valence electrons are counted as,

(1C×4e)+(3H×1e)+(1N×5e)+(2O×6e)=4e+3e+5e+12e=24e

The bonds and lone pairs are added in the given arrangement of atoms. The valid Lewis structure is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  9

Figure 6

Conclusion

The valid Lewis structure for the given compound is shown in Figure 6.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation: A valid Lewis structure for the given compound is to be drawn.

Concept introduction: The arrangement of valence electrons among the atoms present in a molecule is represented by the Lewis structure of that molecule. The electron pairs in the molecule are considered to be delocalized.

Answer to Problem 1.43P

The valid Lewis structure for the given compound is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  10

Explanation of Solution

The given compound is HCO2. The atoms are arranged as,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  11

Figure 7

The valence electrons are counted as,

(1C×4e)+(1H×1e)+(2O×6e)=4e+1e+12e=17e

The bonds and lone pairs are added in the given arrangement of atoms. The valid Lewis structure is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  12

Figure 8

Conclusion

The valid Lewis structure for the given compound is shown in Figure 8.

Expert Solution
Check Mark
Interpretation Introduction

(e)

Interpretation: A valid Lewis structure for the given compound is to be drawn.

Concept introduction: The arrangement of valence electrons among the atoms present in a molecule is represented by the Lewis structure of that molecule. The electron pairs in the molecule are considered to be delocalized.

Answer to Problem 1.43P

The valid Lewis structure for the given compound is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  13

Explanation of Solution

The given compound is HCO3. The atoms are arranged as,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  14

Figure 9

The valence electrons are counted as,

(1C×4e)+(1H×1e)+(3O×6e)=4e+1e+18e=23e

The bonds and lone pairs are added in the given arrangement of atoms. The valid Lewis structure is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  15

Figure 10

Conclusion

The valid Lewis structure for the given compound is shown in Figure 10.

Expert Solution
Check Mark
Interpretation Introduction

(f)

Interpretation: A valid Lewis structure for the given compound is to be drawn.

Concept introduction: The arrangement of valence electrons among the atoms present in a molecule is represented by the Lewis structure of that molecule. The electron pairs in the molecule are considered to be delocalized.

Answer to Problem 1.43P

The valid Lewis structure for the given compound is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  16

Explanation of Solution

The given compound is CH2CN. The atoms are arranged as,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  17

Figure 11

The valence electrons are counted as,

(2C×4e)+(2H×1e)+(1N×5e)=8e+2e+5e=15e

The bonds and lone pairs are added in the given arrangement of atoms. The valid Lewis structure is,

Organic Chemistry-Package(Custom), Chapter 1, Problem 1.43P , additional homework tip  18

Figure 12

Conclusion

The valid Lewis structure for the given compound is shown in Figure 12.

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Chapter 1 Solutions

Organic Chemistry-Package(Custom)

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