Sodium borohydride (NaBH4) is a potent inhibitor of aldolase. It is known to ONLY inhibit theenzyme when it is complexed with substrate. Treatment of the enzyme alone has no effect.What is the mechanism for this inhibition? Please draw out the mechanism and show how it inhibits this.

Sodium borohydride (NaBH4) is a potent inhibitor of aldolase. It is known to ONLY inhibit theenzyme when it is complexed with substrate. Treatment of the enzyme alone has no effect.What is the mechanism for this inhibition? Please draw out the mechanism and show how it inhibits this.

Biochemistry

6th Edition

ISBN:9781305577206

Author:Reginald H. Garrett, Charles M. Grisham

Publisher:Reginald H. Garrett, Charles M. Grisham

Chapter26: Synthesis And Degradation Of Nucleotides

Section: Chapter Questions

Problem 11P: The Catabolism of Uric Acid Write a balanced equation for the oxidation of uric acid to glyoxylic...

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Question

Sodium borohydride (NaBH4) is a potent inhibitor of aldolase. It is known to ONLY inhibit the
enzyme when it is complexed with substrate. Treatment of the enzyme alone has no effect.
What is the mechanism for this inhibition?

Please draw out the mechanism and show how it inhibits this.

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a. Compounds A, B, C, and D are known to be intermediates in the pathway for production of protein E. To determine where the block in protein-E production occurred in each individual, the various intermediates were given to each individuals cel Is in culture. After a few weeks of growth with the intermediate, the cells were assayed for the production of protein E. The results for each individuals cells are given in the following table. A plus sign means that protein E was produced after the cells were given the intermediate listed at the top of the column. A minus sign means that the cells still could not produce protein E even after being exposed to the intermediate at the top of the column. Draw the pathway leading to the production of protein E.