+11246.78.9.Transcriptionalstop sequenceТАTА boxATGТАAUGUAAHere is a diagram of a human gene in the genome. The bar above it is indicating differentregions of the gene sequence.7. Which region or regions contain the sequences that direct splicing? -8. In which region or regions could a single base pair insertion cause a frameshift mutation(but not because of changed splicing)? -9. In which region or regions might you find sequences that control the amount oftranscription of this gene? +10. In which region or regions could a single base pair deletion cause the mRNA to be onebase pair shorter? -11. Which region or regions usually contain a sequence that controls the secretion of theprotein eproduct? e

The process of transcription catalyzed by RNA Polymerase II in eukaryotes gives rise to the pre-m…

Answered: 1 4 6 7 8. 9. Transcriptional stop…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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G-LO37 Identify the consequences of mutations in different regions of a gene. The image below represents two strands of DNA: the top one corresponds to a healthy individual, and the bottom one of a sibling potentially affected with a disease due to genetic mutations Mutation 1 A + с AUA ACA AUG Met ACG GUU GUC GUA GUG Val GCU GCC GCA GCG It will result in mRNA produced Mutation 2 It will result in no mRNA produced 500 AGG The protein produced will be normal 500 + GGG Ala The Select all that applies about Mutation 1 (position -6): AAGLys AGA Arg GGU GGC GGA GGG GAC Asp GAA Glu GAGJ Gly The protein produced will have a different amino acid 1235 ATT 1235 TTT 070 2070 ALL The mutation occurs in the promoter region, and this means that the mRNA cannot be produced 1535 The mRNA and protein will both be normal because the mutation occurs outside of the consensus region of the promoter G 1535 с Affected
36.Start with two exons and an intervening intron. Include the cap and poly-A tail in your starting pre-mRNA. Show 2’-OH, 3’-OH, O-P-O phosphodiester bonds for the two transesterification reactions that splice exon 1 and exon 2. Be sure to include the branchpoint A and intron consensus sequences. You will need to show where the incoming -OH attacks the O-P-O bond to allow correct splicing in the lariat and between exons. Make your arrows precise. Show the lariat with the consensus sequences. Whenever possible, show 5’ and 3’ ends. Explain the fate of the lariat after it forms?
25. Given the following mRNA codons and amino acids, construct a polypeptide from this DNA strand. DNA AAT GGT CCA CCG CTG 1TI 111 11 T Ou GGT GGC GIC MRNA Amino Acids UUA = leucine %3D GAC = asparginine GGU = glycine GGC = glycine CCA = proline %3D AMAM b iwi tant neto10 e 2obitoabun St
4) Shown below is a schematic drawing of a gene, with the transcription unit divided into numbered regions. The arrows indicate transcription initiation sites, "D" indicates a splice donor site, "A" indicates a splice acceptor site, and "An" indicates a polyadenylation signal. Indicate all the possible mRNAs that could be produced from this gene (you don't need to draw new schematics - just list the regions that would be included in each mRNA by number)
7. F. State if/how Remedios' mutation changes the amino acid sequence and describe the effect that change has, if any, on the protein.
37.
4. For the gene drawn below, transcription begins at the boxed A/T base pair. a. Identify the promoter, template and coding strand. b. Transcribe c. Translate 5'- TTGGAATTGTGAATGGATAACAATGTGACACAGGAAACAGCTAAGTAGATGTTT -3' 1 54 3'- AACCTTAACACTTACCTATTGTTACACTGTGTCCTTTGACGATTCATCTACAAA -5' ---+--- ---+--- ---+---- ---+--- ---+---
12.please match with the type of mutation
1. A portion of the template strand of a DNA molecule that codes for the 5'-end of an mRNA has the following nucleotide sequence. Give the primary structure of the polypeptide (use 3-letter amino acid codes), beginning with the most common translation initiation codon, that will be specified by this portion of the gene. Be sure to label the ends of the polypeptide. 3'-TTTTACGGGAATTAGAGTCGCAGGATG-5'
8. As explained in the text, the cause of many geneticdiseases cannot yet be discerned by analyzing wholeexome/genome sequences. But in some of theseseemingly intractable cases, important clues can beobtained by looking at mRNAs or proteins, ratherthan at the DNA.a. As you will see in more detail in later chapters, it ispossible to use single-molecule methods to sequence cDNA copies of millions of mRNA molecules from any particular tissue cheaply. Howcould you sometimes use such information to finda disease gene? When would this information benoninformative?b. A technique called Western blotting allows you toexamine any protein for which you have an antibody; it is possible to see differences in size oramount of that protein. How could you sometimesuse such information to find a disease gene? Whenwould this information be noninformative?

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