a. Explanation Given data: The delivered power to tube is 700 W . The percentage of conversion of power is 1 % . The wavelength of x-rays is 0.030 nm . Formula used: Write the expression for photon energy ( E ) . E = h c λ (1) Here, λ is wavelength, c is speed of light , which is 3 × 10 8 m s , and h is Planck’s constant, which is 6.63 × 10 − 34 J ⋅ s . Consider the expression for number of photons emitted per second ( N ) . N = P E (2) Here, P is delivered power per photon. Substitute 0.030 nm for λ , 3 × 10 8 m s for c , and 6.63 × 10 − 34 J ⋅ s for h in equation (1), E = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 0.030 nm = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 0 b. To determine The equivalent dose in Sv by person.

College Physics: A Strategic Approach (3rd Edition)

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ISBN: 9780321879721

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Rutherford's scattering experiment

Rutherford’s scattering experiment is also known as the gold foil experiment. This experiment disproved the plum pudding model of J.J. Thomson. In a gold foil experiment, high-energy alpha particles are made to strike a thin gold foil. The scattered alph…

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Chapter P.7, Problem 18P

To determine

The number of emitted x-ray photons per second approximately.

To determine

The equivalent dose in Sv by person.

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Chapter P.7, Problem 17P

Chapter P.7, Problem 19P

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The number of emitted x-ray photons per second approximately.

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The number of emitted x-ray photons per second approximately.

The equivalent dose in Sv by person.

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