Explanation Given data: v = 15 k m h , M = 68 k g and P = 480 W . Formula used: Write the expression to find rate of heat transfer ( Q ) in terms of specific heat ( c ) . Q = M c Δ T (1) Here, M is the mass of the water, Δ T is the temperature difference, and c is the specific heat, which is known as 3400 J kg ⋅ K for mammalian bodies. Consider the conversion factor from W to J s . 1 W = 1 J s Consider the conversion factor from minutes to seconds. 1 m = 60 s Consider the conversion factor from Kelvin to ° C . 1 K = 1 ° C Consider the 25% of power is converted to the mechanical energy of motion, then the remaining 75% ( 100 % − 25 % ) is converted to thermal energy in his body. Therefore, Chemical energy being converted to thermal energy ( Q ) = 75 % ( P ) Substitute 480 W for P , Q = 75 % ( 480 W ) = 75 100 ( 480 W ) = 0.75 ( 480 W ) = 360 W Rearrange equation (1)

College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321879721

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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First law of Thermodynamics

The word thermodynamics consists of two words: thermo- and dynamics. Dynamics means the study of motion. The field of thermodynamics is all about the study of the movement of heat. In a more meaningful way, it is stated as the study of the transfer of en…

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Chapter P.3, Problem 9P

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The temperature of cyclist body increase in 10 minutes of riding, to the nearest 0.1°C .

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Chapter P.3, Problem 8P

Chapter P.3, Problem 10P

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The temperature of cyclist body increase in 10 minutes of riding, to the nearest 0.1 ° C .

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The temperature of cyclist body increase in 10 minutes of riding, to the nearest 0.1°C .

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