Biochemistry, The Molecular Basis of Life, 6th Edition
6th Edition
ISBN: 9780190259204
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Chapter 9, Problem 5Q
Summary Introduction
To review:
The path of the radio-labeled carbon in the citric acid cycle (CAC) along with the reason behind two turns of this cycle is required to be run prior to the release of carbon atoms in the form of carbon dioxide (14 CO2).
Introduction:
The citric acid cycle is an essential biochemical pathway that releases chemical energy stored in the acetyl CoA. This process takes place inside the mitochondria. Acetyl CoA produced from the pyruvate by the enzyme pyruvate dehydrogenase. In CAC, two molecules of carbon dioxide get released in every turn of the cycle.
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The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism
of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help
To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?
To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!
Chapter 9 Solutions
Biochemistry, The Molecular Basis of Life, 6th Edition
Ch. 9 - Prob. 1QCh. 9 - Prob. 2QCh. 9 - Prob. 3QCh. 9 - Prob. 4QCh. 9 - Prob. 5QCh. 9 - Prob. 6QCh. 9 - Prob. 7QCh. 9 - Prob. 1RQCh. 9 - Prob. 2RQCh. 9 - Prob. 3RQ
Ch. 9 - Prob. 4RQCh. 9 - Prob. 5RQCh. 9 - Prob. 6RQCh. 9 - Prob. 7RQCh. 9 - Prob. 8RQCh. 9 - Prob. 9RQCh. 9 - Prob. 10RQCh. 9 - Prob. 11RQCh. 9 - Prob. 12RQCh. 9 - Prob. 13RQCh. 9 - Prob. 14RQCh. 9 - Prob. 15RQCh. 9 - Prob. 16RQCh. 9 - Prob. 17RQCh. 9 - Prob. 18RQCh. 9 - Prob. 19RQCh. 9 - Prob. 20RQCh. 9 - Prob. 21RQCh. 9 - Prob. 22RQCh. 9 - Prob. 23RQCh. 9 - Prob. 24RQCh. 9 - Prob. 25RQCh. 9 - Prob. 26RQCh. 9 - Prob. 27RQCh. 9 - Prob. 28FBCh. 9 - Prob. 29FBCh. 9 - Prob. 30FBCh. 9 - Prob. 31FBCh. 9 - Prob. 32FBCh. 9 - Prob. 33FBCh. 9 - Prob. 34FBCh. 9 - Prob. 35FBCh. 9 - Prob. 36FBCh. 9 - Prob. 37FBCh. 9 - Prob. 38SACh. 9 - Prob. 39SACh. 9 - Prob. 40SACh. 9 - Prob. 41SACh. 9 - Prob. 42SACh. 9 - Prob. 43TQCh. 9 - Prob. 44TQCh. 9 - Prob. 45TQCh. 9 - Prob. 46TQCh. 9 - Prob. 47TQCh. 9 - Prob. 48TQCh. 9 - Prob. 49TQCh. 9 - Prob. 50TQCh. 9 - Prob. 51TQCh. 9 - Prob. 52TQCh. 9 - Prob. 53TQCh. 9 - Prob. 54TQCh. 9 - Prob. 55TQCh. 9 - Prob. 56TQCh. 9 - Prob. 57TQCh. 9 - Prob. 58TQCh. 9 - Prob. 59TQ
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