Biochemistry, The Molecular Basis of Life, 6th Edition
6th Edition
ISBN: 9780190259204
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Question
Chapter 9, Problem 6RQ
Summary Introduction
To review:
Changes in the CAC (citric acid cycle) due to ATP (adenosine triphosphate) exhaustion in the contracting muscle.
Introduction:
Glucose or carbohydrate is a great source of energy, but this energy is produced in three steps in case of an organism who respire in presence of oxygen. These three steps are glycolysis, CAC, and ETC (electron transport chain). Every glucose molecule goes through these steps and gives rise to 38 molecules of ATP, which are used by the muscles during running or walking or exercises.
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The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism
of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help
To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?
To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!
Chapter 9 Solutions
Biochemistry, The Molecular Basis of Life, 6th Edition
Ch. 9 - Prob. 1QCh. 9 - Prob. 2QCh. 9 - Prob. 3QCh. 9 - Prob. 4QCh. 9 - Prob. 5QCh. 9 - Prob. 6QCh. 9 - Prob. 7QCh. 9 - Prob. 1RQCh. 9 - Prob. 2RQCh. 9 - Prob. 3RQ
Ch. 9 - Prob. 4RQCh. 9 - Prob. 5RQCh. 9 - Prob. 6RQCh. 9 - Prob. 7RQCh. 9 - Prob. 8RQCh. 9 - Prob. 9RQCh. 9 - Prob. 10RQCh. 9 - Prob. 11RQCh. 9 - Prob. 12RQCh. 9 - Prob. 13RQCh. 9 - Prob. 14RQCh. 9 - Prob. 15RQCh. 9 - Prob. 16RQCh. 9 - Prob. 17RQCh. 9 - Prob. 18RQCh. 9 - Prob. 19RQCh. 9 - Prob. 20RQCh. 9 - Prob. 21RQCh. 9 - Prob. 22RQCh. 9 - Prob. 23RQCh. 9 - Prob. 24RQCh. 9 - Prob. 25RQCh. 9 - Prob. 26RQCh. 9 - Prob. 27RQCh. 9 - Prob. 28FBCh. 9 - Prob. 29FBCh. 9 - Prob. 30FBCh. 9 - Prob. 31FBCh. 9 - Prob. 32FBCh. 9 - Prob. 33FBCh. 9 - Prob. 34FBCh. 9 - Prob. 35FBCh. 9 - Prob. 36FBCh. 9 - Prob. 37FBCh. 9 - Prob. 38SACh. 9 - Prob. 39SACh. 9 - Prob. 40SACh. 9 - Prob. 41SACh. 9 - Prob. 42SACh. 9 - Prob. 43TQCh. 9 - Prob. 44TQCh. 9 - Prob. 45TQCh. 9 - Prob. 46TQCh. 9 - Prob. 47TQCh. 9 - Prob. 48TQCh. 9 - Prob. 49TQCh. 9 - Prob. 50TQCh. 9 - Prob. 51TQCh. 9 - Prob. 52TQCh. 9 - Prob. 53TQCh. 9 - Prob. 54TQCh. 9 - Prob. 55TQCh. 9 - Prob. 56TQCh. 9 - Prob. 57TQCh. 9 - Prob. 58TQCh. 9 - Prob. 59TQ
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