Biochemistry, The Molecular Basis of Life, 6th Edition
6th Edition
ISBN: 9780190259204
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Question
Chapter 9, Problem 36FB
Summary Introduction
To review:
The given blank space in the statement “In eukaryotic cells, the citric acid cycle occurs in the _______.”
Introduction:
Eukaryotes belong to the Eukaryota domain. The cells of the eukaryotes essentially have a nucleus, which contains the genetic material, a membrane, and also membrane-bound cell organelles. These cells are more complex than a prokaryotic cell (e.g., the cell of a bacteria). Example of a eukaryotic cell includeanyplant or animal cell.
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The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism
of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help
To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?
To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!
Chapter 9 Solutions
Biochemistry, The Molecular Basis of Life, 6th Edition
Ch. 9 - Prob. 1QCh. 9 - Prob. 2QCh. 9 - Prob. 3QCh. 9 - Prob. 4QCh. 9 - Prob. 5QCh. 9 - Prob. 6QCh. 9 - Prob. 7QCh. 9 - Prob. 1RQCh. 9 - Prob. 2RQCh. 9 - Prob. 3RQ
Ch. 9 - Prob. 4RQCh. 9 - Prob. 5RQCh. 9 - Prob. 6RQCh. 9 - Prob. 7RQCh. 9 - Prob. 8RQCh. 9 - Prob. 9RQCh. 9 - Prob. 10RQCh. 9 - Prob. 11RQCh. 9 - Prob. 12RQCh. 9 - Prob. 13RQCh. 9 - Prob. 14RQCh. 9 - Prob. 15RQCh. 9 - Prob. 16RQCh. 9 - Prob. 17RQCh. 9 - Prob. 18RQCh. 9 - Prob. 19RQCh. 9 - Prob. 20RQCh. 9 - Prob. 21RQCh. 9 - Prob. 22RQCh. 9 - Prob. 23RQCh. 9 - Prob. 24RQCh. 9 - Prob. 25RQCh. 9 - Prob. 26RQCh. 9 - Prob. 27RQCh. 9 - Prob. 28FBCh. 9 - Prob. 29FBCh. 9 - Prob. 30FBCh. 9 - Prob. 31FBCh. 9 - Prob. 32FBCh. 9 - Prob. 33FBCh. 9 - Prob. 34FBCh. 9 - Prob. 35FBCh. 9 - Prob. 36FBCh. 9 - Prob. 37FBCh. 9 - Prob. 38SACh. 9 - Prob. 39SACh. 9 - Prob. 40SACh. 9 - Prob. 41SACh. 9 - Prob. 42SACh. 9 - Prob. 43TQCh. 9 - Prob. 44TQCh. 9 - Prob. 45TQCh. 9 - Prob. 46TQCh. 9 - Prob. 47TQCh. 9 - Prob. 48TQCh. 9 - Prob. 49TQCh. 9 - Prob. 50TQCh. 9 - Prob. 51TQCh. 9 - Prob. 52TQCh. 9 - Prob. 53TQCh. 9 - Prob. 54TQCh. 9 - Prob. 55TQCh. 9 - Prob. 56TQCh. 9 - Prob. 57TQCh. 9 - Prob. 58TQCh. 9 - Prob. 59TQ
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