Chapter 8.6, Problem 4CE

To determine

To express $\sin A,\cos A\text{and}\tan A$ as fractions by using the triangle shown below.

  

Answer to Problem 4CE

  $\sin B=\frac{15}{17},\cos B=\frac{8}{17}\&\tan B=\frac{\text{15}}{8}$

Explanation of Solution

Given:

  

Calculation:

In the given triangle,

  $\begin{array}{l}\sin B=\frac{\text{opposite}}{\text{hypotenuse}}\\ =\frac{15}{17}\\ \cos B=\frac{\text{adjacent}}{\text{hypotenuse}}\\ =\frac{8}{17}\\ \tan B=\frac{\text{opposite}}{\text{adjacent}}\\ =\frac{15}{8}\end{array}$