Chapter 8, Problem 20CT

To determine

To find the value of $x$ in the triangle shown below.

  

Answer to Problem 20CT

  $x=31$

Explanation of Solution

Given:

  

Calculation:

In the given triangle,

  $\begin{array}{l}\tan {42}^{\circ }=\frac{28}{x}\\ \Rightarrow x=\frac{28}{\tan {42}^{\circ }}\\ \Rightarrow x=31.0971\\ \Rightarrow x\approx 31\end{array}$