Chapter 8.6, Problem 2CE

To determine

To express $\sin A,\cos A\text{and}\tan A$ as fractions by using the triangle shown below.

  

Answer to Problem 2CE

  $\sin A=\frac{7}{25},\cos A=\frac{24}{25}\&\tan A=\frac{\text{7}}{24}$

Explanation of Solution

Given:

  

Calculation:

In the given triangle,

  $\begin{array}{l}\sin A=\frac{\text{opposite}}{\text{hypotenuse}}\\ =\frac{7}{25}\\ \cos A=\frac{\text{adjacent}}{\text{hypotenuse}}\\ =\frac{24}{25}\\ \tan A=\frac{\text{opposite}}{\text{adjacent}}\\ =\frac{7}{24}\end{array}$