McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
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Chapter 8.6, Problem 13WE

a.

To determine

To find: the value of x in radical form.

a.

Expert Solution
Check Mark

Answer to Problem 13WE

The value of x is 115

Explanation of Solution

Given Information: A right angled triangle with hypotenuse and altitude given as 14 and 9 units respectively. The acute angle and adjacent side is shown as y0and x respectively.

Formula used:

The relationship between the legs of right triangle (shown in figure below) a , b and its hypotenuse c is obtained by using Pythagoras theorem.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 8.6, Problem 13WE , additional homework tip  1

It can be expressed as,

  c2=a2+b2c=a2+b2

Calculation: Consider the triangle given below.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 8.6, Problem 13WE , additional homework tip  2

Applying Pythagoras theorem, the value of x which represents the adjacent side can be calculated as,

  x=14292=115

b.

To determine

To find: the value of y using trigonometry.

Also, to find the value of x using y

b.

Expert Solution
Check Mark

Answer to Problem 13WE

The measure of y is 6 units

Explanation of Solution

Given Information: A right angled triangle with hypotenuse and altitude given as 14 and 9 units respectively. The acute angle and adjacent side is shown as y0and x respectively.

Formula used:

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 8.6, Problem 13WE , additional homework tip  3

In a right triangle, the sine of an angle is the ratio of opposite side to the hypotenuse of the triangle expressed as,

  sinB=ac

Also, the tangent of an angle is the ratio of opposite side to the adjacent side of the triangle expressed as,

  tanB=ab

Calculation: Consider the triangle given below. The sine of angle y can be expressed as,

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 8.6, Problem 13WE , additional homework tip  4

  siny°=914=0.6429 .

Therefore, angle y can be calculated as,

  y°=sin1(0.6429)=40.005°40°

Now, the value of x can be calculated by considering tangent of angle y0.

  tany°=9xtan40°=9x

Rearranging the equation yields the value of x as,

  x=9tan40°=90.8393=10.7238

c.

To determine

To check: if the value of x in parts a. and b. are in reasonable agreement.

c.

Expert Solution
Check Mark

Answer to Problem 13WE

Yes

Explanation of Solution

Given Information: A right angled triangle with hypotenuse and altitude given as 14 and 9 units respectively. The acute angle and adjacent side is shown as y0and x respectively. The value of x in both parts a. and b. are to be considered.

The value of x calculated in part a. using the Pythagoras theorem is,

  x=115=10.7238

Now, the value of x found in part b. using trigonometry relations is,

  x=10.7238

It can be seen that, the values are in reasonable agreement with each other and are exactly the same in both cases.

Chapter 8 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 8.1 - Prob. 11CECh. 8.1 - Prob. 12CECh. 8.1 - Prob. 13CECh. 8.1 - Prob. 14CECh. 8.1 - Prob. 15CECh. 8.1 - Prob. 16CECh. 8.1 - Prob. 17CECh. 8.1 - Prob. 1WECh. 8.1 - Prob. 2WECh. 8.1 - Prob. 3WECh. 8.1 - Prob. 4WECh. 8.1 - Prob. 5WECh. 8.1 - Prob. 6WECh. 8.1 - Prob. 7WECh. 8.1 - Prob. 8WECh. 8.1 - Prob. 9WECh. 8.1 - Prob. 10WECh. 8.1 - Prob. 11WECh. 8.1 - Prob. 12WECh. 8.1 - Prob. 13WECh. 8.1 - Prob. 14WECh. 8.1 - Prob. 15WECh. 8.1 - Prob. 16WECh. 8.1 - Prob. 17WECh. 8.1 - Prob. 18WECh. 8.1 - Prob. 19WECh. 8.1 - Prob. 20WECh. 8.1 - Prob. 21WECh. 8.1 - Prob. 22WECh. 8.1 - Prob. 23WECh. 8.1 - Prob. 24WECh. 8.1 - Prob. 25WECh. 8.1 - Prob. 26WECh. 8.1 - Prob. 27WECh. 8.1 - Prob. 28WECh. 8.1 - Prob. 29WECh. 8.1 - Prob. 30WECh. 8.1 - Prob. 31WECh. 8.1 - Prob. 32WECh. 8.1 - Prob. 33WECh. 8.1 - Prob. 34WECh. 8.1 - Prob. 35WECh. 8.1 - Prob. 36WECh. 8.1 - Prob. 37WECh. 8.1 - Prob. 38WECh. 8.1 - Prob. 39WECh. 8.1 - Prob. 40WECh. 8.1 - Prob. 41WECh. 8.1 - Prob. 42WECh. 8.1 - Prob. 43WECh. 8.1 - 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Prob. 3ST1Ch. 8.4 - Prob. 4ST1Ch. 8.4 - Prob. 5ST1Ch. 8.4 - Prob. 6ST1Ch. 8.4 - Prob. 7ST1Ch. 8.5 - Prob. 1CECh. 8.5 - Prob. 2CECh. 8.5 - Prob. 3CECh. 8.5 - Prob. 4CECh. 8.5 - Prob. 5CECh. 8.5 - Prob. 6CECh. 8.5 - Prob. 7CECh. 8.5 - Prob. 8CECh. 8.5 - Prob. 9CECh. 8.5 - Prob. 10CECh. 8.5 - Prob. 11CECh. 8.5 - Prob. 1WECh. 8.5 - Prob. 2WECh. 8.5 - Prob. 3WECh. 8.5 - Prob. 4WECh. 8.5 - Prob. 5WECh. 8.5 - Prob. 6WECh. 8.5 - Prob. 7WECh. 8.5 - Prob. 8WECh. 8.5 - Prob. 9WECh. 8.5 - Prob. 10WECh. 8.5 - Prob. 11WECh. 8.5 - Prob. 12WECh. 8.5 - Prob. 13WECh. 8.5 - Prob. 14WECh. 8.5 - Prob. 15WECh. 8.5 - Prob. 16WECh. 8.5 - Prob. 17WECh. 8.5 - Prob. 18WECh. 8.5 - Prob. 19WECh. 8.5 - Prob. 20WECh. 8.5 - Prob. 21WECh. 8.5 - Prob. 22WECh. 8.5 - Prob. 23WECh. 8.5 - Prob. 24WECh. 8.5 - Prob. 25WECh. 8.5 - Prob. 26WECh. 8.5 - Prob. 27WECh. 8.5 - Prob. 28WECh. 8.5 - Prob. 29WECh. 8.5 - Prob. 30WECh. 8.6 - Prob. 1CECh. 8.6 - Prob. 2CECh. 8.6 - Prob. 3CECh. 8.6 - Prob. 4CECh. 8.6 - Prob. 5CECh. 8.6 - Prob. 6CECh. 8.6 - 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Prob. 11WECh. 8.7 - Prob. 12WECh. 8.7 - Prob. 13WECh. 8.7 - Prob. 14WECh. 8.7 - Prob. 1ST2Ch. 8.7 - Prob. 2ST2Ch. 8.7 - Prob. 3ST2Ch. 8.7 - Prob. 4ST2Ch. 8.7 - Prob. 5ST2Ch. 8.7 - Prob. 6ST2Ch. 8.7 - Prob. 7ST2Ch. 8.7 - Prob. 8ST2Ch. 8.7 - Prob. 9ST2Ch. 8.7 - Prob. 1ECh. 8.7 - Prob. 2ECh. 8.7 - Prob. 3ECh. 8.7 - Prob. 4ECh. 8.7 - Prob. 5ECh. 8.7 - Prob. 6ECh. 8.7 - Prob. 7ECh. 8.7 - Prob. 8ECh. 8.7 - Prob. 9ECh. 8.7 - Prob. 10ECh. 8 - Prob. 1CRCh. 8 - Prob. 2CRCh. 8 - Prob. 3CRCh. 8 - Prob. 4CRCh. 8 - Prob. 5CRCh. 8 - Prob. 6CRCh. 8 - Prob. 7CRCh. 8 - Prob. 8CRCh. 8 - Prob. 9CRCh. 8 - Prob. 10CRCh. 8 - Prob. 11CRCh. 8 - Prob. 12CRCh. 8 - Prob. 13CRCh. 8 - Prob. 14CRCh. 8 - Prob. 15CRCh. 8 - Prob. 16CRCh. 8 - Prob. 17CRCh. 8 - Prob. 18CRCh. 8 - Prob. 19CRCh. 8 - Prob. 20CRCh. 8 - Prob. 21CRCh. 8 - Prob. 22CRCh. 8 - Prob. 23CRCh. 8 - Prob. 24CRCh. 8 - Prob. 1CTCh. 8 - Prob. 2CTCh. 8 - Prob. 3CTCh. 8 - Prob. 4CTCh. 8 - Prob. 5CTCh. 8 - Prob. 6CTCh. 8 - Prob. 7CTCh. 8 - Prob. 8CTCh. 8 - Prob. 9CTCh. 8 - Prob. 10CTCh. 8 - Prob. 11CTCh. 8 - Prob. 12CTCh. 8 - Prob. 13CTCh. 8 - Prob. 14CTCh. 8 - Prob. 15CTCh. 8 - Prob. 16CTCh. 8 - Prob. 17CTCh. 8 - Prob. 18CTCh. 8 - Prob. 19CTCh. 8 - Prob. 20CTCh. 8 - Prob. 21CTCh. 8 - Prob. 22CTCh. 8 - Prob. 23CTCh. 8 - Prob. 24CTCh. 8 - Prob. 25CTCh. 8 - Prob. 26CTCh. 8 - Prob. 27CTCh. 8 - Prob. 1CURCh. 8 - Prob. 2CURCh. 8 - Prob. 3CURCh. 8 - Prob. 4CURCh. 8 - Prob. 5CURCh. 8 - Prob. 6CURCh. 8 - Prob. 7CURCh. 8 - Prob. 8CURCh. 8 - Prob. 9CURCh. 8 - Prob. 10CURCh. 8 - Prob. 11CURCh. 8 - Prob. 12CURCh. 8 - Prob. 13CURCh. 8 - Prob. 14CURCh. 8 - Prob. 15CURCh. 8 - Prob. 16CURCh. 8 - Prob. 17CUR
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