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Concept explainers
a.
To find: the value of x in radical form.
a.
![Check Mark](/static/check-mark.png)
Answer to Problem 13WE
The value of x is
Explanation of Solution
Given Information: A right angled
Formula used:
The relationship between the legs of right triangle (shown in figure below) a , b and its hypotenuse c is obtained by using Pythagoras theorem.
It can be expressed as,
Calculation: Consider the triangle given below.
Applying Pythagoras theorem, the value of x which represents the adjacent side can be calculated as,
b.
To find: the value of y using trigonometry.
Also, to find the value of x using y
b.
![Check Mark](/static/check-mark.png)
Answer to Problem 13WE
The measure of y is
Explanation of Solution
Given Information: A right angled triangle with hypotenuse and altitude given as 14 and 9 units respectively. The acute angle and adjacent side is shown as y0and x respectively.
Formula used:
In a right triangle, the sine of an angle is the ratio of opposite side to the hypotenuse of the triangle expressed as,
Also, the tangent of an angle is the ratio of opposite side to the adjacent side of the triangle expressed as,
Calculation: Consider the triangle given below. The sine of angle y can be expressed as,
Therefore, angle y can be calculated as,
Now, the value of x can be calculated by considering tangent of angle y0.
Rearranging the equation yields the value of x as,
c.
To check: if the value of x in parts a. and b. are in reasonable agreement.
c.
![Check Mark](/static/check-mark.png)
Answer to Problem 13WE
Yes
Explanation of Solution
Given Information: A right angled triangle with hypotenuse and altitude given as 14 and 9 units respectively. The acute angle and adjacent side is shown as y0and x respectively. The value of x in both parts a. and b. are to be considered.
The value of x calculated in part a. using the Pythagoras theorem is,
Now, the value of x found in part b. using trigonometry relations is,
It can be seen that, the values are in reasonable agreement with each other and are exactly the same in both cases.
Chapter 8 Solutions
McDougal Littell Jurgensen Geometry: Student Edition Geometry
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