Chapter 8, Problem 22CT

To determine

To find the value of $x$ in the triangle shown below.

  

Answer to Problem 22CT

  $x^{\circ }={37}^{\circ }$

Explanation of Solution

Given:

  

Calculation:

In the given triangle,

  $\begin{array}{l}\sin x^{\circ }=\frac{3}{5}\\ \Rightarrow x^{\circ }={\sin }^{-1}\left(\frac{3}{5}\right)\\ \Rightarrow x^{\circ }=36.8698\\ \Rightarrow x^{\circ }\approx {37}^{\circ }\end{array}$