Chapter 8.4, Problem 1CE

To determine

The value of x.

Answer to Problem 1CE

The value of x is $6\sqrt{2}$

Explanation of Solution

Given information:

The given figure is,

  

Here, in the figure one angle is $45°$ and second is $45°$ .

So third angle will be $90°$ .

  $\begin{array}{l}\sin \theta =\frac{perpendicular}{hypotenuse}\\ \sin 45°=\frac{6}{x}\\ \frac{1}{\sqrt{2}}=\frac{6}{x}\\ x=6\sqrt{2}\end{array}$

Therefore, the value of x is $6\sqrt{2}$ .