Chapter 8.6, Problem 3QQ

Interpretation Introduction

Interpretation:

The volume in litre of $\text{0}\text{.200}\text{M}$$\text{NaCl}$ which contains $\text{0}\text{.200}\text{mole}$$\text{NaCl}$ has to be determined.

Concept introduction:

Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

  $\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$