Chapter 8, Problem 8.62EP

Interpretation Introduction

Interpretation:

Mass–volume percent concentration of $\text{6}\text{.0 M NaOH}$ solution has to be calculated.

Concept Introduction:

Molarity:

Concentration of solution is given in the term of molarity it is given by,

    $\text{M}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Liter}\text{of}\text{solution}}$

Mole of substance is given by,

    $\text{Mole}\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$

Mass–volume percent is given by,

    $\text{=}\frac{\text{Mass}\text{of}\text{solute}\text{in}\text{(g)}}{\text{Volume}\text{of}\text{solution}\text{(mL)}}\text{×}\text{100}$