Chapter 8, Problem 20MCQ

To determine

The value of $\sin N$ .

Answer to Problem 20MCQ

  $\sin N=0.92$

Explanation of Solution

Given:

The given triangle is:

  

Calculation:

The value of $\sin N$ will be:

  $\begin{array}{l}\sin N=\frac{Opp.}{Hyp.}\\ \sin N=\frac{36}{39}\\ \sin N=0.92\\ \sin N=\frac{12}{13}\end{array}$