Chapter 8.3, Problem 37PPS

To determine

The value of x, y and z.

Answer to Problem 37PPS

  $\begin{array}{l}x=9\sqrt{2}\\ y=6\sqrt{3}\\ z=12\sqrt{3}\end{array}$

Explanation of Solution

Given:

The given figure is:

Calculation:

The value of x, y and z will be:

  $\begin{array}{l}l\sqrt{2}=h\\ \sqrt{2}x=18\\ x=\frac{18}{\sqrt{2}}\\ x=\frac{18}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}\\ x=9\sqrt{2}\end{array}$

Also,

  $\begin{array}{l}l=\sqrt{3}s\\ 18=\sqrt{3}y\\ y=\frac{18}{\sqrt{3}}\\ y=\frac{18\sqrt{3}}{3}\\ y=6\sqrt{3}\\ \text{and}\\ h=2s\\ z=2\left(6\sqrt{3}\right)\\ z=12\sqrt{3}\end{array}$