Chapter 8.4, Problem 1CYP

To determine

The values of the trigonometric quantities.

Answer to Problem 1CYP

  $\begin{array}{l}\sin J=0.38,\cos J=0.92,\tan J=0.42\\ \sin K=0.92,\cos K=0.38,\tan K=2.4\end{array}$

Explanation of Solution

Given:

  

Calculation:

For angle J,

  $\begin{array}{l}\sin J=\frac{P}{H}=\frac{5}{13}=0.38\\ \cos J=\frac{B}{H}=\frac{12}{13}=0.92\\ \tan J=\frac{P}{B}=\frac{5}{12}=0.42\end{array}$

For angle K,

  $\begin{array}{l}\sin K=\frac{P}{H}=\frac{12}{13}=0.92\\ \cos K=\frac{B}{H}=\frac{5}{13}=0.38\\ \tan K=\frac{P}{B}=\frac{12}{5}=2.4\end{array}$