Chapter 8.2, Problem 39PPS

To determine

The value of perimeter and area of the figure.

Answer to Problem 39PPS

  $P=36$

  $A=60$

Explanation of Solution

Given:

The given figure is:

Calculation:

According to Pythagorean Theorem,

  $\begin{array}{l}{\left(13\right)}^2={\left(5\right)}^2+{\left(x\right)}^2\\ 169=25+x^2\\ x^2=144\\ x=\sqrt{144}\\ x=12\end{array}$

The perimeter of the figure will be:

  $\begin{array}{l}P=13+13+10\\ P=36\end{array}$

The area of the figure will be:

  $\begin{array}{l}A=\frac{1}{2}\left(10\right)\left(12\right)\\ A=\left(5\right)\left(12\right)\\ A=60\end{array}$