Chapter 8, Problem 29SGR

To determine

The value of $\tan A$

Answer to Problem 29SGR

  $\tan A=\text{0}\text{.42}$

Explanation of Solution

Given:

The given figure is:

Calculation:

The value of $\tan A$ will be:

  $\begin{array}{l}\tan A=\frac{\text{Opp}\text{.}}{\text{Adj}\text{.}}\\ \tan A=\frac{\text{10}}{\text{24}}\\ \tan A=\frac{\text{5}}{\text{12}}\\ \tan A=\text{0}\text{.42}\end{array}$