Chapter 8.7, Problem 30PPS

To determine

To calculation:

Sum of given pair of vector.

Answer to Problem 30PPS

Sum of given pair of vector $\langle -1,12\rangle +\langle 14,2\rangle$ is $\langle 13,14\rangle$ .

Explanation of Solution

Given information:

  $\langle -1,12\rangle +\langle 14,2\rangle$ .

Calculation:

Given vectors are $\langle -1,12\rangle +\langle 14,2\rangle$ .

Let,

  $\begin{array}{l}\stackrel{\rightharpoonup }{a}=\langle -1,12\rangle \\ \stackrel{\rightharpoonup }{b}=\langle 14,2\rangle \end{array}$

Add the two vectors by adding each coordinate component together,

  $\begin{array}{l}\stackrel{\rightharpoonup }{a}+\stackrel{\rightharpoonup }{b}=\langle a_1+b_1,a_2+b_2\rangle \\ \stackrel{\rightharpoonup }{a}+\stackrel{\rightharpoonup }{b}=\langle -1,12\rangle +\langle 14,2\rangle \\ \stackrel{\rightharpoonup }{a}+\stackrel{\rightharpoonup }{b}=\langle \left(-1\right)+14,12+2\rangle \\ \stackrel{\rightharpoonup }{a}+\stackrel{\rightharpoonup }{b}=\langle 13,14\rangle \end{array}$

Hence, Sum of given pair of vector $\langle -1,12\rangle +\langle 14,2\rangle$ is $\langle 13,14\rangle$ .