Chapter 8, Problem 22SGR

To determine

The values of x and y.

Answer to Problem 22SGR

  $\begin{array}{l}x=5\sqrt{3}\\ y=10\sqrt{3}\end{array}$

Explanation of Solution

Given:

The given figure is:

Calculation:

According to $30°-60°-90°$ Triangle Theorem,

  $\begin{array}{l}l=\sqrt{3}s\\ 15=\sqrt{3}x\\ \frac{15}{\sqrt{3}}=x\\ x=\frac{15}{\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}\\ x=5\sqrt{3}\\ \text{and}\\ h=2s\\ y=2\left(5\sqrt{3}\right)\\ y=10\sqrt{3}\end{array}$