Chapter 8.2, Problem 55STP

To determine

The perimeter of square 3.

Answer to Problem 55STP

  $250\text{units}$

Explanation of Solution

Given:

Calculation:

The side length of square 1 is:

  $\begin{array}{l}=\frac{150}{4}\\ =37.5\text{units}\end{array}$

The side length of square 2 is:

  $\begin{array}{l}=\frac{200}{4}\\ =50\text{units}\end{array}$

According to Pythagorean Theorem,

  $\begin{array}{l}{a}^2+b^2=c^2\\ {37.5}^2+{50}^2=x^2\\ 2500+1406.25=x^2\\ x^2=3906.25\\ x=62.5\end{array}$

The perimeter of square 3 will be:

  $\begin{array}{l}=4\left(62.5\right)\\ =250\text{units}.\end{array}$