The open-chain form of the given β − D − monosaccharide has to be drawn. Concept introduction: The Fischer projection formula can be drawn by using the following rules. Ø For α and β configurations, if in the cyclic form of Haworth projection, OH group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula. Ø If in the cyclic form of Haworth projection, OH group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula. Ø For β configuration, the position of OH group at the first carbon with respect to CH 2 OH group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

Question

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Answer 1

Question

Chapter 7, Problem 7.84EP

(a)

Interpretation Introduction

Interpretation: The open-chain form of the given $β−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(a)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $β−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 1

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 2

The open-chain form of the given Haworth projection formula of an $β−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 3

Thus, in this open-chain form of the given $β−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. But as it is a $β−D−monosaccharide$ , thus $OH$ group at the first carbon with respect to $CH2OH$ group is drawn at the left side of the open-chain structure. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(b)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(b)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 4

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 5

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 6

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(c)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(c)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 7

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 8

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 9

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(d)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(d)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 10

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 11

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 12

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

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Answer 2

Question

Chapter 7, Problem 7.84EP

(a)

Interpretation Introduction

Interpretation: The open-chain form of the given $β−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(a)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $β−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 1

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 2

The open-chain form of the given Haworth projection formula of an $β−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 3

Thus, in this open-chain form of the given $β−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. But as it is a $β−D−monosaccharide$ , thus $OH$ group at the first carbon with respect to $CH2OH$ group is drawn at the left side of the open-chain structure. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(b)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(b)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 4

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 5

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 6

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(c)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(c)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 7

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 8

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 9

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(d)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(d)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 10

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 11

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 12

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

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Answer 3

Question

Chapter 7, Problem 7.84EP

(a)

Interpretation Introduction

Interpretation: The open-chain form of the given $β−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(a)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $β−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 1

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 2

The open-chain form of the given Haworth projection formula of an $β−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 3

Thus, in this open-chain form of the given $β−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. But as it is a $β−D−monosaccharide$ , thus $OH$ group at the first carbon with respect to $CH2OH$ group is drawn at the left side of the open-chain structure. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(b)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(b)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 4

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 5

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 6

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(c)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(c)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 7

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 8

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 9

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(d)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(d)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 10

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 11

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 12

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 7, Problem 7.84EP

(a)

Interpretation Introduction

Interpretation: The open-chain form of the given $β−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(a)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $β−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 1

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 2

The open-chain form of the given Haworth projection formula of an $β−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 3

Thus, in this open-chain form of the given $β−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. But as it is a $β−D−monosaccharide$ , thus $OH$ group at the first carbon with respect to $CH2OH$ group is drawn at the left side of the open-chain structure. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(b)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(b)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 4

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 5

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 6

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(c)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(c)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 7

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 8

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 9

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(d)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(d)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 10

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 11

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 12

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 7, Problem 7.84EP

(a)

Interpretation Introduction

Interpretation: The open-chain form of the given $β−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(a)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $β−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 1

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 2

The open-chain form of the given Haworth projection formula of an $β−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 3

Thus, in this open-chain form of the given $β−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. But as it is a $β−D−monosaccharide$ , thus $OH$ group at the first carbon with respect to $CH2OH$ group is drawn at the left side of the open-chain structure. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(b)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(b)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 4

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 5

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 6

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(c)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(c)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 7

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 8

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 9

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

(d)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(d)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 10

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 11

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 12

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

Answer 6

Chapter 7, Problem 7.84EP

(a)

Interpretation Introduction

Interpretation: The open-chain form of the given $β−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(a)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $β−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 1

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 2

The open-chain form of the given Haworth projection formula of an $β−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 3

Thus, in this open-chain form of the given $β−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. But as it is a $β−D−monosaccharide$ , thus $OH$ group at the first carbon with respect to $CH2OH$ group is drawn at the left side of the open-chain structure. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

Answer 7

Chapter 7, Problem 7.84EP

(a)

Interpretation Introduction

Interpretation: The open-chain form of the given $β−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

Answer 8

(a)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $β−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 1

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 2

The open-chain form of the given Haworth projection formula of an $β−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 3

Thus, in this open-chain form of the given $β−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. But as it is a $β−D−monosaccharide$ , thus $OH$ group at the first carbon with respect to $CH2OH$ group is drawn at the left side of the open-chain structure. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

Answer 13

(b)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(b)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 4

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 5

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 6

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

Answer 14

(b)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

Answer 15

(b)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 4

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 5

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 6

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

Answer 20

(c)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(c)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 7

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 8

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 9

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

Answer 21

(c)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

Answer 22

(c)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 7

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 8

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 9

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

Answer 27

(d)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

(d)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 10

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 11

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 12

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.

Answer 28

(d)

Interpretation Introduction

Interpretation: The open-chain form of the given $α−D−monosaccharide$ has to be drawn.

Concept introduction: The Fischer projection formula can be drawn by using the following rules.

Ø For $α$ and $β$ configurations, if in the cyclic form of Haworth projection, $OH$ group is placed below the ring then the same hydroxyl group is drawn at the right position in Fischer projection formula.

Ø If in the cyclic form of Haworth projection, $OH$ group is placed above the ring then the same hydroxyl group is drawn at the left position in Fischer projection formula.

Ø For $β$ configuration, the position of $OH$ group at the first carbon with respect to $CH2OH$ group always remains in the same direction and in the Fischer projection formula it is placed at the left side.

Answer 29

(d)

Expert Solution

Answer to Problem 7.84EP

The open-chain form of the given $α−D−monosaccharide$ is,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 10

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

The given Haworth projection formula is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 11

The open-chain form of the given Haworth projection formula of an $α−D−monosaccharide$ is shown as,

Organic And Biological Chemistry, Chapter 7, Problem 7.84EP , additional homework tip 12

Thus, in this open-chain form of the given $α−D−monosaccharide$ , $CH2OH$ group is placed at the last carbon. The hydroxyl group that is placed below the cyclic ring is then drawn at the right-side position of the open-chain form of monosaccharide. The hydroxyl group that is placed above the cyclic ring is then drawn at the left-side position of the open-chain form of monosaccharide.