Chemical Principles: The Quest for Insight
Chemical Principles: The Quest for Insight
7th Edition
ISBN: 9781464183959
Author: Peter Atkins, Loretta Jones, Leroy Laverman
Publisher: W. H. Freeman
bartleby

Videos

Question
Book Icon
Chapter 6, Problem 6K.1E

(a)

Interpretation Introduction

Interpretation:

From the following redox reaction, which elements undergoing oxidation, reduction and their initial and final oxidation number has to be determined.

  H+(aq)+Cr2O72-(aq)+C2H5OH(aq)Cr3+(aq)+C2H4O(aq)+H2O(l)

Concept Introduction:

Net ionic equation:

Net ionic equation is defined as the specific species that only involves to a particular reaction. This type of equations is generally used in acid-base neutralization reactions and redox reactions.

(a)

Expert Solution
Check Mark

Answer to Problem 6K.1E

The Cr is undergoing reduction reaction and their initial and final oxidation number is +6 and +3, respectively. The C is undergoing oxidation reaction and their initial and final oxidation number is 2 and 1, respectively.

Explanation of Solution

The unbalanced skeletal equation for the reaction is

  H+(aq)+Cr2O72-(aq)+C2H5OH(aq)Cr3+(aq)+C2H4O(aq)+H2O(l)

Reduction reaction:

The oxidation number of Cr is decreased from +6 to +2, therefore this is reduction reaction.

  Cr2O72-(aq)Cr3+(aq)

Oxidation number of Cr is calculated from Cr2O72-(aq) is given below;

Oxidation number of O is 2

  2x+7×(-2)=-22x=-2+142x=12x=6

Therefore, the oxidation number of Cr present in Cr2O72-(aq) is +6.

Oxidation number of Cr3+ is +3.

Oxidation reaction:

The oxidation number of C is increased from 2 to 1, therefore this is oxidation reaction

  C2H5OH(aq)C2H4O(aq)

Oxidation number of C is calculated from C2H5OH(aq) is given below;

Oxidation number of O is 2

Oxidation number of H is +1

  2x+5-2+1=02x+4=02x=-4x=-2

Therefore, the oxidation number of C present in C2H5OH(aq) is 2.

Oxidation number of C is calculated from C2H4O(aq) is given below;

Oxidation number of O is 2

Oxidation number of H is +1

  2x+4-2=02x+2=02x=-2x=-1

Therefore, the oxidation number of C present in C2H5OH(aq) is 1.

Therefore, the Cr is undergoing reduction reaction and their initial and final oxidation number is +6 and +3, respectively. The C is undergoing oxidation reaction and their initial and final oxidation number is 2 and 1, respectively.

(b)

Interpretation Introduction

Interpretation:

The oxidation half-reaction balanced equation has to be derived.

Concept introduction:

Refer to part (a).

(b)

Expert Solution
Check Mark

Answer to Problem 6K.1E

The balanced oxidation half-reaction equation is

  C2H5OH(aq)C2H4O(aq)+2H+(aq)+2e-

Explanation of Solution

Oxidation half-reaction:

The oxidation number of C is increased from 2 to 1, therefore this is oxidation reaction.

  C2H5OH(aq)C2H4O(aq)

Balance the H atom by adding H+ ion on the right side

  C2H5OH(aq)C2H4O(aq)+2H+

Balance the net charges by adding the electrons.

Here, in left side, the net charge is 0 and the right side the net charge is +2, therefore it required 2 electrons on the right side to reduce the charge from +2 to 0.

  C2H5OH(aq)C2H4O(aq)+2H+(aq)+2e-

Therefore, the balanced oxidation half-reaction is,

  C2H5OH(aq)C2H4O(aq)+2H+(aq)+2e-

(c)

Interpretation Introduction

Interpretation:

The reduction half-reaction balanced equation has to be derived.

Concept introduction:

Refer to part (a).

(c)

Expert Solution
Check Mark

Answer to Problem 6K.1E

The balanced reduction half-reaction equation is

  Cr2O72-(aq)+14H+(aq)+6e-2Cr3+(aq)+7H2O(l)

Explanation of Solution

Reduction half-reaction:

The oxidation number of Cr is decreased from +6 to +3, therefore this is reduction reaction.

  Cr2O72-(aq)Cr3+(aq)

Balance the equation except H and O.

  Cr2O72-(aq)2Cr3+(aq)

Balance the O atom by adding H2O right side

  Cr2O72-(aq)2Cr3+(aq)+7H2O

Balance the H atom by adding H+ ion on the left side

  Cr2O72-(aq)+14H+2Cr3+(aq)+7H2O

Balancing the net charges by adding electrons.

Here, in left side, the net charge is +12 and the right side the net charge is +6, therefore it required 6 electrons on the left side to reduce the charge from +12 to +6.

  Cr2O72-(aq)+14H+(aq)+6e-2Cr3+(aq)+7H2O(l)

Therefore, the balanced reduction half-reaction is

  Cr2O72-(aq)+14H+(aq)+6e-2Cr3+(aq)+7H2O(l)

(d)

Interpretation Introduction

Interpretation:

A balanced redox equation for the combined half reactions has to be derived.

Concept introduction:

Refer to part (a).

(d)

Expert Solution
Check Mark

Answer to Problem 6K.1E

A balanced redox equation for the combined half reactions is

  Cr2O72-(aq)+3C2H5OH(aq)+8H+(aq)2Cr3+(aq)+3C2H4O(aq)+7H2O(l)

Explanation of Solution

Now add the two half reactions together. Match the number of electrons in each side.  Because in oxidation half reaction 2 electrons are lost and in reduction half reaction 6 electron is gained. Therefore, multiply the oxidation half reaction by 6 and the reduction half reaction by 2.

  2Cr2O72-(aq)+28H+(aq)+12e-4Cr3+(aq)+14H2O(l)6C2H5OH(aq)6C2H4O(aq)+12H+(aq)+12e-

Add the equation and cancel the common ions and electrons in each side of the arrow.

  2Cr2O72-(aq)+6C2H5OH(aq)+16H+(aq)4Cr3+(aq)+6C2H4O(aq)+14H2O(l)

Divide by 2 each side of the arrow.

  Cr2O72-(aq)+3C2H5OH(aq)+8H+(aq)2Cr3+(aq)+3C2H4O(aq)+7H2O(l)

Therefore, the balanced net ionic equation the above reaction is,

  Cr2O72-(aq)+3C2H5OH(aq)+8H+(aq)2Cr3+(aq)+3C2H4O(aq)+7H2O(l)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 6 Solutions

Chemical Principles: The Quest for Insight

Ch. 6 - Prob. 6A.5ECh. 6 - Prob. 6A.6ECh. 6 - Prob. 6A.7ECh. 6 - Prob. 6A.8ECh. 6 - Prob. 6A.9ECh. 6 - Prob. 6A.10ECh. 6 - Prob. 6A.11ECh. 6 - Prob. 6A.12ECh. 6 - Prob. 6A.13ECh. 6 - Prob. 6A.14ECh. 6 - Prob. 6A.15ECh. 6 - Prob. 6A.16ECh. 6 - Prob. 6A.17ECh. 6 - Prob. 6A.18ECh. 6 - Prob. 6A.19ECh. 6 - Prob. 6A.20ECh. 6 - Prob. 6A.21ECh. 6 - Prob. 6A.22ECh. 6 - Prob. 6A.23ECh. 6 - Prob. 6A.24ECh. 6 - Prob. 6B.1ASTCh. 6 - Prob. 6B.1BSTCh. 6 - Prob. 6B.2ASTCh. 6 - Prob. 6B.2BSTCh. 6 - Prob. 6B.3ASTCh. 6 - Prob. 6B.3BSTCh. 6 - Prob. 6B.1ECh. 6 - Prob. 6B.2ECh. 6 - Prob. 6B.3ECh. 6 - Prob. 6B.4ECh. 6 - Prob. 6B.5ECh. 6 - Prob. 6B.6ECh. 6 - Prob. 6B.7ECh. 6 - Prob. 6B.8ECh. 6 - Prob. 6B.9ECh. 6 - Prob. 6B.10ECh. 6 - Prob. 6B.11ECh. 6 - Prob. 6B.12ECh. 6 - Prob. 6C.1ASTCh. 6 - Prob. 6C.1BSTCh. 6 - Prob. 6C.2ASTCh. 6 - Prob. 6C.2BSTCh. 6 - Prob. 6C.3ASTCh. 6 - Prob. 6C.3BSTCh. 6 - Prob. 6C.1ECh. 6 - Prob. 6C.2ECh. 6 - Prob. 6C.3ECh. 6 - Prob. 6C.4ECh. 6 - Prob. 6C.5ECh. 6 - Prob. 6C.6ECh. 6 - Prob. 6C.7ECh. 6 - Prob. 6C.8ECh. 6 - Prob. 6C.9ECh. 6 - Prob. 6C.10ECh. 6 - Prob. 6C.11ECh. 6 - Prob. 6C.12ECh. 6 - Prob. 6C.13ECh. 6 - Prob. 6C.14ECh. 6 - Prob. 6C.15ECh. 6 - Prob. 6C.16ECh. 6 - Prob. 6C.17ECh. 6 - Prob. 6C.18ECh. 6 - Prob. 6C.19ECh. 6 - Prob. 6C.20ECh. 6 - Prob. 6C.21ECh. 6 - Prob. 6C.22ECh. 6 - Prob. 6D.1ASTCh. 6 - Prob. 6D.1BSTCh. 6 - Prob. 6D.2ASTCh. 6 - Prob. 6D.2BSTCh. 6 - Prob. 6D.3ASTCh. 6 - Prob. 6D.3BSTCh. 6 - Prob. 6D.4ASTCh. 6 - Prob. 6D.4BSTCh. 6 - Prob. 6D.5ASTCh. 6 - Prob. 6D.5BSTCh. 6 - Prob. 6D.6ASTCh. 6 - Prob. 6D.6BSTCh. 6 - Prob. 6D.1ECh. 6 - Prob. 6D.2ECh. 6 - Prob. 6D.3ECh. 6 - Prob. 6D.4ECh. 6 - Prob. 6D.5ECh. 6 - Prob. 6D.6ECh. 6 - Prob. 6D.7ECh. 6 - Prob. 6D.8ECh. 6 - Prob. 6D.9ECh. 6 - Prob. 6D.11ECh. 6 - Prob. 6D.12ECh. 6 - Prob. 6D.13ECh. 6 - Prob. 6D.14ECh. 6 - Prob. 6D.15ECh. 6 - Prob. 6D.16ECh. 6 - Prob. 6D.17ECh. 6 - Prob. 6D.18ECh. 6 - Prob. 6D.19ECh. 6 - Prob. 6D.20ECh. 6 - Prob. 6D.21ECh. 6 - Prob. 6D.22ECh. 6 - Prob. 6E.1ASTCh. 6 - Prob. 6E.1BSTCh. 6 - Prob. 6E.2ASTCh. 6 - Prob. 6E.2BSTCh. 6 - Prob. 6E.3ASTCh. 6 - Prob. 6E.1ECh. 6 - Prob. 6E.2ECh. 6 - Prob. 6E.3ECh. 6 - Prob. 6E.4ECh. 6 - Prob. 6E.5ECh. 6 - Prob. 6E.6ECh. 6 - Prob. 6E.7ECh. 6 - Prob. 6E.8ECh. 6 - Prob. 6E.9ECh. 6 - Prob. 6E.10ECh. 6 - Prob. 6E.11ECh. 6 - Prob. 6E.12ECh. 6 - Prob. 6E.13ECh. 6 - Prob. 6E.14ECh. 6 - Prob. 6E.15ECh. 6 - Prob. 6E.16ECh. 6 - Prob. 6E.17ECh. 6 - Prob. 6E.18ECh. 6 - Prob. 6F.1ASTCh. 6 - Prob. 6F.1BSTCh. 6 - Prob. 6F.2ASTCh. 6 - Prob. 6F.2BSTCh. 6 - Prob. 6F.1ECh. 6 - Prob. 6F.2ECh. 6 - Prob. 6F.3ECh. 6 - Prob. 6F.4ECh. 6 - Prob. 6F.5ECh. 6 - Prob. 6F.6ECh. 6 - Prob. 6F.7ECh. 6 - Prob. 6F.9ECh. 6 - Prob. 6F.10ECh. 6 - Prob. 6G.1ASTCh. 6 - Prob. 6G.1BSTCh. 6 - Prob. 6G.2ASTCh. 6 - Prob. 6G.2BSTCh. 6 - Prob. 6G.3ASTCh. 6 - Prob. 6G.3BSTCh. 6 - Prob. 6G.4ASTCh. 6 - Prob. 6G.4BSTCh. 6 - Prob. 6G.1ECh. 6 - Prob. 6G.3ECh. 6 - Prob. 6G.4ECh. 6 - Prob. 6G.5ECh. 6 - Prob. 6G.6ECh. 6 - Prob. 6G.7ECh. 6 - Prob. 6G.8ECh. 6 - Prob. 6G.9ECh. 6 - Prob. 6G.11ECh. 6 - Prob. 6G.12ECh. 6 - Prob. 6G.13ECh. 6 - Prob. 6G.14ECh. 6 - Prob. 6G.15ECh. 6 - Prob. 6G.16ECh. 6 - Prob. 6G.19ECh. 6 - Prob. 6G.20ECh. 6 - Prob. 6H.1ASTCh. 6 - Prob. 6H.1BSTCh. 6 - Prob. 6H.2ASTCh. 6 - Prob. 6H.2BSTCh. 6 - Prob. 6H.3ASTCh. 6 - Prob. 6H.3BSTCh. 6 - Prob. 6H.4ASTCh. 6 - Prob. 6H.4BSTCh. 6 - Prob. 6H.5ASTCh. 6 - Prob. 6H.5BSTCh. 6 - Prob. 6H.1ECh. 6 - Prob. 6H.3ECh. 6 - Prob. 6H.9ECh. 6 - Prob. 6H.10ECh. 6 - Prob. 6H.15ECh. 6 - Prob. 6H.16ECh. 6 - Prob. 6H.21ECh. 6 - Prob. 6H.22ECh. 6 - Prob. 6H.23ECh. 6 - Prob. 6H.24ECh. 6 - Prob. 6H.25ECh. 6 - Prob. 6H.26ECh. 6 - Prob. 6H.27ECh. 6 - Prob. 6H.28ECh. 6 - Prob. 6H.29ECh. 6 - Prob. 6H.30ECh. 6 - Prob. 6H.31ECh. 6 - Prob. 6H.32ECh. 6 - Prob. 6I.1ASTCh. 6 - Prob. 6I.1BSTCh. 6 - Prob. 6I.2ASTCh. 6 - Prob. 6I.2BSTCh. 6 - Prob. 6I.3ASTCh. 6 - Prob. 6I.3BSTCh. 6 - Prob. 6I.4ASTCh. 6 - Prob. 6I.4BSTCh. 6 - Prob. 6I.1ECh. 6 - Prob. 6I.2ECh. 6 - Prob. 6I.3ECh. 6 - Prob. 6I.4ECh. 6 - Prob. 6I.5ECh. 6 - Prob. 6I.6ECh. 6 - Prob. 6I.7ECh. 6 - Prob. 6I.8ECh. 6 - Prob. 6I.9ECh. 6 - Prob. 6I.10ECh. 6 - Prob. 6I.11ECh. 6 - Prob. 6I.12ECh. 6 - Prob. 6J.1ASTCh. 6 - Prob. 6J.1BSTCh. 6 - Prob. 6J.2ASTCh. 6 - Prob. 6J.2BSTCh. 6 - Prob. 6J.1ECh. 6 - Prob. 6J.2ECh. 6 - Prob. 6J.3ECh. 6 - Prob. 6J.4ECh. 6 - Prob. 6J.9ECh. 6 - Prob. 6J.10ECh. 6 - Prob. 6J.11ECh. 6 - Prob. 6J.15ECh. 6 - Prob. 6J.17ECh. 6 - Prob. 6K.1ASTCh. 6 - Prob. 6K.1BSTCh. 6 - Prob. 6K.2ASTCh. 6 - Prob. 6K.2BSTCh. 6 - Prob. 6K.1ECh. 6 - Prob. 6K.2ECh. 6 - Prob. 6K.3ECh. 6 - Prob. 6K.4ECh. 6 - Prob. 6K.5ECh. 6 - Prob. 6K.6ECh. 6 - Prob. 6K.7ECh. 6 - Prob. 6K.8ECh. 6 - Prob. 6L.1ASTCh. 6 - Prob. 6L.1BSTCh. 6 - Prob. 6L.2ASTCh. 6 - Prob. 6L.2BSTCh. 6 - Prob. 6L.3ASTCh. 6 - Prob. 6L.3BSTCh. 6 - Prob. 6L.1ECh. 6 - Prob. 6L.2ECh. 6 - Prob. 6L.3ECh. 6 - Prob. 6L.4ECh. 6 - Prob. 6L.5ECh. 6 - Prob. 6L.7ECh. 6 - Prob. 6L.9ECh. 6 - Prob. 6M.1ASTCh. 6 - Prob. 6M.1BSTCh. 6 - Prob. 6M.2ASTCh. 6 - Prob. 6M.2BSTCh. 6 - Prob. 6M.3ASTCh. 6 - Prob. 6M.3BSTCh. 6 - Prob. 6M.4ASTCh. 6 - Prob. 6M.4BSTCh. 6 - Prob. 6M.1ECh. 6 - Prob. 6M.2ECh. 6 - Prob. 6M.9ECh. 6 - Prob. 6M.10ECh. 6 - Prob. 6N.1ASTCh. 6 - Prob. 6N.1BSTCh. 6 - Prob. 6N.2ASTCh. 6 - Prob. 6N.2BSTCh. 6 - Prob. 6N.3BSTCh. 6 - Prob. 6N.4ASTCh. 6 - Prob. 6N.4BSTCh. 6 - Prob. 6N.1ECh. 6 - Prob. 6N.2ECh. 6 - Prob. 6N.5ECh. 6 - Prob. 6N.6ECh. 6 - Prob. 6N.7ECh. 6 - Prob. 6N.9ECh. 6 - Prob. 6N.10ECh. 6 - Prob. 6N.11ECh. 6 - Prob. 6N.12ECh. 6 - Prob. 6N.21ECh. 6 - Prob. 6N.23ECh. 6 - Prob. 6O.1ASTCh. 6 - Prob. 6O.1BSTCh. 6 - Prob. 6O.2ASTCh. 6 - Prob. 6O.2BSTCh. 6 - Prob. 6O.3ASTCh. 6 - Prob. 6O.3BSTCh. 6 - Prob. 6O.4ASTCh. 6 - Prob. 6O.4BSTCh. 6 - Prob. 6O.1ECh. 6 - Prob. 6O.2ECh. 6 - Prob. 6O.3ECh. 6 - Prob. 6O.4ECh. 6 - Prob. 6O.5ECh. 6 - Prob. 6O.6ECh. 6 - Prob. 6O.7ECh. 6 - Prob. 6O.8ECh. 6 - Prob. 6O.9ECh. 6 - Prob. 6O.10ECh. 6 - Prob. 6O.11ECh. 6 - Prob. 6O.12ECh. 6 - Prob. 6O.13ECh. 6 - Prob. 6O.14ECh. 6 - Prob. 6O.15ECh. 6 - Prob. 6O.16ECh. 6 - Prob. 6.1ECh. 6 - Prob. 6.3ECh. 6 - Prob. 6.4ECh. 6 - Prob. 6.5ECh. 6 - Prob. 6.6ECh. 6 - Prob. 6.8ECh. 6 - Prob. 6.9ECh. 6 - Prob. 6.10ECh. 6 - Prob. 6.11ECh. 6 - Prob. 6.12ECh. 6 - Prob. 6.13ECh. 6 - Prob. 6.14ECh. 6 - Prob. 6.25ECh. 6 - Prob. 6.40ECh. 6 - Prob. 6.41ECh. 6 - Prob. 6.43ECh. 6 - Prob. 6.45ECh. 6 - Prob. 6.46ECh. 6 - Prob. 6.47ECh. 6 - Prob. 6.51ECh. 6 - Prob. 6.53ECh. 6 - Prob. 6.65ECh. 6 - Prob. 6.75ECh. 6 - Prob. 6.77E
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Acid-Base Equilibrium; Author: Bozeman Science;https://www.youtube.com/watch?v=l5fk7HPmo5g;License: Standard YouTube License, CC-BY
Introduction to Titrimetric analysis; Author: Vidya-mitra;https://www.youtube.com/watch?v=uykGVfn9q24;License: Standard Youtube License